list names in an array

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Barakat Ibrhim
Barakat Ibrhim 2019-6-13
评论： Adam Danz 2019-6-14
I have many files that i want to list their names in an array but the name is full for example
F:\New\checkfiles\C100.csv
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the cyclist
the cyclist 2019-6-13
It would be handy if dir took an argument, allowing specification of the full path in the output. It seems like this would be a common enough thing to want to do.
Adam Danz
Adam Danz 2019-6-13
Agreed. I suggested testing d.name because the OP stated that it was only returning file name when it should be returning the file extension as well.

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回答（2 个）

Guillaume
Guillaume 2019-6-13
A lot simpler than all that has been suggested:
foldercontent = dir('C:\somewhere\*.csv');
filelist = fullfile({foldercontent.folder}, {foldercontent.name}); %that's all that is needed.
As said, if a string array is needed, string will convert the cell array of char vectors into a string array
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Stephen23
Stephen23 2019-6-14
编辑：Stephen23 2019-6-14
+1 fullfile is definitely the way to go.
It is highly unlikely that constructing filenames is going to be a bottleneck in the code.
Adam Danz
Adam Danz 2019-6-14
Definitely clairity over milliseconds.

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the cyclist
the cyclist 2019-6-13
I'm pretty sure there is a better, simpler way to do this, but I believe this does what you want:
s = dir;
fileList = cellfun(@(x,y)[x,'/',y],{s.folder}',{s.name}','UniformOutput',false);
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Adam Danz
Adam Danz 2019-6-13
"I'm pretty sure there is a better, simpler way..."
s = dir;
fileList = strcat({s.folder}',repmat({'/'},size(s)),{s.name}');
Stephen23
Stephen23 2019-6-14
"I'm pretty sure there is a better, simpler way..."
S = dir(...);
F = cellfun(@fullfile,{S.folder}',{S.name}','uni',0);
Or simply:
F = fullfile({S.folder},{S.name});

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