list names in an array
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I have many files that i want to list their names in an array but the name is full for example
F:\New\checkfiles\C100.csv
5 个评论
Barakat Ibrhim
2019-6-13
Adam Danz
2019-6-13
It sounds like you're doing something wrong.
Does your code look like this?
d = dir('C:\Users\name\Documents\MATLAB\');
% list all file
{d.name}'
the cyclist
2019-6-13
It would be handy if dir took an argument, allowing specification of the full path in the output. It seems like this would be a common enough thing to want to do.
Adam Danz
2019-6-13
Agreed. I suggested testing d.name because the OP stated that it was only returning file name when it should be returning the file extension as well.
回答（2 个）
Guillaume
2019-6-13
A lot simpler than all that has been suggested:
foldercontent = dir('C:\somewhere\*.csv');
filelist = fullfile({foldercontent.folder}, {foldercontent.name}); %that's all that is needed.
As said, if a string array is needed, string will convert the cell array of char vectors into a string array
4 个评论
That is more simpler to read and more intuitive. However, for those obsessed with speed, The Cyclist's solution is 1.56x faster and my solution is 1.84x faster; probably due to avoiding overhead in fullfile (median speed comparison of 10,000 repetitions of each single line solution).
Guillaume
2019-6-14
I would argue that clarity completely trumps speed in this case particularly as the speed difference would be insignificant compared to the file IO that will inevitably follow.
Adam Danz
2019-6-14
Definitely clairity over milliseconds.
the cyclist
2019-6-13
I'm pretty sure there is a better, simpler way to do this, but I believe this does what you want:
s = dir;
fileList = cellfun(@(x,y)[x,'/',y],{s.folder}',{s.name}','UniformOutput',false);
4 个评论
Barakat Ibrhim
2019-6-13
the cyclist
2019-6-13
编辑：the cyclist
2019-6-13
string(fileList)
will convert the cell array to a string array (at least in R2018b).
Adam Danz
2019-6-13
"I'm pretty sure there is a better, simpler way..."
s = dir;
fileList = strcat({s.folder}',repmat({'/'},size(s)),{s.name}');
Stephen23
2019-6-14
"I'm pretty sure there is a better, simpler way..."
S = dir(...);
F = cellfun(@fullfile,{S.folder}',{S.name}','uni',0);
Or simply:
F = fullfile({S.folder},{S.name});
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2019-6-13
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