How to resolve the "Index exceeds matrix dimensions" error ?

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if true
data = getdata(vid,50,'double','cell');
for i=1:5:100
data{i}(:,:,1)=(data{i}(:,:,1))+(data{i+1}(:,:,1))+(data{i+2}(:,:,1))+ ...
(data{i+3}(:,:,1))+(data{i+4}(:,:,1))/5;
data{i}(:,:,3)=(data{i}(:,:,3))+(data{i+1}(:,:,3))+(data{i+2}(:,:,3))+...
(data{i+3}(:,:,3))+(data{i+4}(:,:,3))/5;
data{i}(:,:,2)=(data{i}(:,:,2))+(data{i+1}(:,:,2))+(data{i+2}(:,:,2))+...
(data{i+3}(:,:,2))+(data{i+4}(:,:,2))/5;
end
end
[EDITED, Jan, code formatted - Please do this by your own, thanks!]

回答(3 个)

Dishant Arora
Dishant Arora 2012-8-26
dbstop if error
use this before executing,u will get an idea where exactly this error occurs
  9 个评论
sadhna
sadhna 2012-9-1
i cant understand how to solve this prob ..plz help me out of this...

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serena dsouza
serena dsouza 2020-8-3
Hi, I am getting same error in this following loop but on selected samples , even though they are of same length, Only Some of them giving error. Here, I am trying to do framing of audio signal.Can anyone help me in this.Thank you.
n=round(length(xOut)/no_frames); %find how many samples will each frame contain
P=zeros(n,no_frames);
for j=0:no_frames-1
P(:,j+1)=xOut(1+n*j:n*(j+1));
end

maryam ahmad
maryam ahmad 2021-6-2
Hi i want to 3D plot of x, y anad z and for that i have table of 1000x1 (name 'Rouser1') and have 3 variables as following
x(n) = seq (n)-seq (n-1);
y(n) = seq (n-1) - seq (n-2);
z(n) = seq (n-2) - seq (n-3);
% in this seq will be the 'values of Rouser1' and Variable of Rouser1 is 'VarName1'
% so how im suppose to make a 3D plot?

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