how to solve 'Error using | Matrix dimensions must agree. ' ?
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Hello Dears
i have the error that i mentioned in question and i do not know how i can solve it.
while (Lia2_One_Three ~= zeros(length(Lia2_One_Three),1) | Lia2_Two_Three ~= zeros(length(Lia2_Two_Three),1))
row_n2_three_step = randperm(length(area_2) / 2, n2_three_step_delayed_measurements) ;
Lia2_One_Three = ismember(row_n2_one_step, row_n2_three_step) ;
Lia2_Two_Three = ismember(row_n2_two_step, row_n2_three_step) ;
end
it seems that this error says that 'Lia2_One_Three ~= zeros(length(Lia2_One_Three)) ' and
' Lia2_Two_Three ~= zeros(length(Lia2_Two_Three))' should have same dimention. i just want to say that while the first condition or second condition is true, produce ' row_n2_three_step' again.
'Lia2_One_Three ' and ' Lia2_Two_Three ' are vectors with different dimentions.
4 个评论
KALYAN ACHARJYA
2019-6-18
编辑：KALYAN ACHARJYA
2019-6-18
OK, If the code is small, can you share the complete code, so that we can try on it?
neda eskandari
2019-6-18
neda eskandari
2019-6-18
neda eskandari
2019-6-18
采纳的回答
James Tursa
2019-6-18
编辑：James Tursa
2019-6-18
Maybe this line:
while (Lia2_One_Three ~= zeros(length(Lia2_One_Three),1) | Lia2_Two_Three ~= zeros(length(Lia2_Two_Three),1))
could be this instead?
while ( any(Lia2_One_Three(:)) || any(Lia2_Two_Three(:)) )
I'm guessing a bit on what I think you want the test to do.
Note that the ~= and | operators are element-wise operators, which I am guessing is not what you really want to use here.
5 个评论
neda eskandari
2019-6-18
neda eskandari
2019-6-18
neda eskandari
2019-6-18
James Tursa
2019-6-18
The any( ) functions tests for nonzeros, so the ~=0 part in your proposed code is redundant.
neda eskandari
2019-6-18
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