Is there a method to linear index to a transpose matrix without taking the transpose?

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Douglas Farinelli
Douglas Farinelli 2019-6-18
评论： Douglas Farinelli 2019-6-19
Is there a method to linear index to a transpose matrix without taking the transpose?
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Image Analyst
Image Analyst 2019-6-19
What code is that? Where did you attach it? Who wrote it?
And what is wrong with using the transpose operator '? Why do you need a different way?

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Douglas Farinelli
Douglas Farinelli 2019-6-18
Yes want to index the matrix by rows vs columns. I suppose i can use the function ind2sub and switch the row and col.
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Walter Roberson
Walter Roberson 2019-6-18
Yes.
Note: for a 2D matrix, ind2sub is (column_number - 1) * number_of_rows + row_number .
You can therefore optimize the access (row_number, column_number) to the transpose (column_number, row_number) as
(row_number - 1) * number_of_rows + column_number

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