Store arrays produced by for loop
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Hello,
I am writing a script that produces an array, vq, every iteration through a loop. I am trying to save each version of vq so I can compare each vq row by row later on. I suppose storing each vq as a column in a matrix would be ideal since each vq is the same length. This is my code:
for m=B1(1:end,:)
for n = B2(1:end,:)
for p=1:length(B1)
H=find(time_dec > m(p) & time_dec < n(p));
[Alt,index]=unique(Alt(H));
temp=Temp(H);
xq=30.5:17.5:2000;
vq=interp1(Alt,temp(index),xq)';
end
end
end
Any suggestions?
Thank you very much.
5 个评论
Stephen23
2019-7-1
What sizes are B1 and B2 ?
Olivia Booth-Howe
2019-7-1
Olivia Booth-Howe
2019-7-1
Jan
2019-7-1
"Doesn't work" is not useful to describe a problem.
This looks strange:
for m=B1(1:end,:)
"They are vectors of length 2, 3, 4, 5, or 6." - please post their size(). It matters, if they are row or column vectors.
Olivia Booth-Howe
2019-7-1
采纳的回答
KALYAN ACHARJYA
2019-7-1
编辑：KALYAN ACHARJYA
2019-7-1
-The code works fine to produce the vq I want, I just need to save it as a matrix and simply putting vq(p)-
You can save it as structure cell array, as I have no idea of the length of vq would be. Hence I have choosen different variable I.
vq={}
l=1;
for
.......
vq{l}=
l=l+1
end
or
If the length is p, then you can use vq{p}=.. too. On such case remove l.
vq={}
for
.......
vq{p}=
end
3 个评论
Olivia Booth-Howe
2019-7-1
KALYAN ACHARJYA
2019-7-1
Always welcome @Olivia
Jan
2019-7-2
+1. Exactly.
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