n+1 in formula

10 次查看（过去 30 天）

B 2019-7-3

回答： Dheeraj Singh 2019-7-17

Hi, could someone help me to put the next formula in matlab?

The sum goes to n-1: 1/2*T* sum(abs(AP[n+1]*ML[n] - AP[n]*ML[n+1])).

The main problem is the n+1 how can i do this.

Stephen23 2019-7-3

B's "Answer" moved here:

Is this better? AP and ML are about the x and y coordinates when someone is standing still.

Raj 2019-7-3

编辑：Raj 2019-7-3

" main problem is the n+1 " I am still not quite sure what is the problem. Is this what you are looking for?

count=0;
for n=1:N-1
count=count+abs((AP(n+1)*ML(n))-(AP(n)*ML(n+1)));
end
count=(0.5*count)/T;

Dheeraj Singh 2019-7-17

Hi,

I understand that by “put” you mean you want to implement it without using loops.

The following code implements the above formula without using loops using random values of “AP” and “ML”

T=2;
n=100
AP=rand(n,1);
ML=rand(n,1);
i=1:n-1;
j=i+1;
val=sum(abs(AP(j).*ML(i)-AP(i).*ML(j)))/(2*T)

MATLAB

在 Help Center 和 File Exchange 中查找有关 MATLAB 的更多信息

Find the treasures in MATLAB Central and discover how the community can help you!

Translated by