A question on input and output arguments in a function, interesting.
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Hello fellows users of MATLAB. Let me state my question, I really appreciate your attention. I am programming the code of a program which represents a distillation column with controllers. As part of the global iterative process I need to stablish some functions which calculate Entalphies, Liquid Flowrates, Temperatures and Vapor compositions. My problem is that I have a function that needs as input argument a Temperature value(TBUBLE) and the expresion in the function also calculates a temperature value because the program needs it, this is an output value (TBUBLE). In your experience: Is it possible to declare a function with a name for an input argument exactly the same as the name for an output argument?, as in my case TBUBLE.
Thank you .
function [TBUBLE,YBUBLE]=BUBPT(XS,PEP,AVPP,BVPP,TBUBLE)
*
XSS=XS(1:5);
%PEPP=PEP
AVPPP=AVPP(1:5);
BVPPP=BVPP(1:5);
% LAZO=0.0;
% Initial values
SUMYTA=0.0;
FSLOPEE=0.0;
while LAZO <=50
for K=1:5
%TBUBLE IS NEEDED AS INPUT ARGUMENT
PSS(K)=exp(BVPPP(K)+AVPPP(K)/(TBUBLE+460.));
YBUBLE(K)=PSS(K)*XSS(K)/PEP;
SUMYTA=SUMYTA+YBUBLE(K);
end
if abs((SUMYTA-1.)<=0.00001)
% disp('TEMP-LAZO')
break
else
FEE=SUMYTA*PEP-PEP;
TSQQ=(TBUBLE+460.)^2;
end
for K=1:5
FSLOPEE=FSLOPEE-AVPPP(K)*XSS(K)*PSS(K)/TSQQ;
end
%TBUBLE is calculated again
TBUBLE=TBUBLE-FEE/FSLOPEE;
% Increase counting
LAZO=LAZO+1;
disp('TEMP-LAZO')
end
end
2 个评论
abs((SUMYTA-1.) <= 0.00001) does most likely not, what you are expecting: the ABS() is applied after the <= comparison. But the operation abs(true) or abs(false) is not really useful. Do you mean:
abs(SUMYTA-1.) <= 0.00001
Pepe Vázquez
2012-9-2
采纳的回答
Walter Roberson
2012-9-2
0 个投票
Yes, it is valid to have an output argument name that is the same as an input argument name. Indeed, there are some internal optimizations that can only occur in this situation.
更多回答（1 个）
Matt Fig
2012-9-2
Even a one-line function is possible in MATLAB. This is a valid function...
function num = myecho(num)
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2012-9-2
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