I am trying to plot y=x^2sin(x), where x is from 0 to 2pi. I have defined x using the linspace command, but matlab does not agree with the (x.^2) part. Is there a concept I am missing?

12 次查看（过去 30 天）
Tianna
Tianna 2012-9-3
回答： Ernesto Martinez 2019-4-22
>> x=linspace(0,2*pi);
>> y=(x.^2)*sin(x);
Error using *
Inner matrix dimensions must agree.

请先登录，再回答此问题。

采纳的回答

Ernesto Martinez
Ernesto Martinez 2019-4-22
y= (x.^2).*sin(x.^-1);

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 2-D and 3-D Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by