integral(exp(double integral)) ?===>integral of riemann

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Marwen Tarhouni 2019-7-20

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https://ww2.mathworks.cn/matlabcentral/answers/472636-integral-exp-double-integral-integral-of-riemann

评论： Marwen Tarhouni 2019-7-21

采纳的回答： Sulaymon Eshkabilov

在 MATLAB Online 中打开

Hi,

i have an equation to 3 unknown (x,y theta)

i try this code

a            =2.2;
b            =0:10:100; 
r            = 50;
for i = 1:length(b)
    
 bin=100;
 resultat=0;
 
     for k=1:bin
      y=k*r/bin;
      eq1= @(x,theta) exp(-b(i).*(sqrt(x.^2.*(cos(theta)).^2+(x.*sin(theta)-y).^2).*x)) ;
      In2=integral2(eq1,0,r,0,2*pi);
      resultat=resultat+ exp(-a* (1-In2))*2*y/(r^2);
 
     end
end

==== >result does not work correctly

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John D'Errico 2019-7-20

Without even looking more carefully at the numbers, as soon as I see this start:

exp(-3.7154e+05*d(i).*(

I will predict your problem is in the form of exponential underflows. The result will be numerical garbage.

Marwen Tarhouni 2019-7-20

编辑：Marwen Tarhouni 2019-7-20

Without this number ,i removed it. It's important to me to solve this equation ,i try this code as solution of my equation but i dont know if it's correctly.

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