The length of the initial condition X0 must match the number of states.

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boutros baqain 2019-8-4

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https://ww2.mathworks.cn/matlabcentral/answers/474818-the-length-of-the-initial-condition-x0-must-match-the-number-of-states

评论： Johannes James 2021-3-14

hello everyone i cant seem to figure out what the problem with my code. it keeps giving me an error regarding the initial state. any help would be appreciated.

thanks!

here is my code.

A= [0 1 0; 0 0 1; -52 -30 -4];
B = [0;0;1];
C = [20 1 0];
D = [0];
% compute open loop state space 
sys_OL = ss(A,B,C,D);
% scaling the B matrix 
w = -C/A*B;
% open loop state space with scaled input 
sys_OL2 = ss(A, B/w, C, D);  
p0 = 5; 
Ts = 2; 
term = pi^2 +log(p0/100)^2;
zeta = abs(log(p0/100))/sqrt(term);
wn   = 4 /Ts/zeta;
beta = sqrt(1-zeta^2); 
p3 = 10 * zeta *wn 
eigDes = [-zeta*wn+j*wn*beta -zeta*wn-j*wn*beta -p3 -20+i]
% compute the close loop 
Ae= [0 1 0 0; 0 0 1 0; -52 -30 -4 0; -20 -1 0 0];
Be = [0;0;1; 0];
Ce = [20 1 0 0];
De = [0];
Br = [0;0;0;1]
Ke = acker(Ae, Be,eigDes)   % gain matrix 
sys_Cl = ss(Ae - Be*Ke, Br ,Ce,De)  %transfer function of close loop
t = 0:0.001:5; 
u = ones(size(t));
x0 = [0.01; 0; 0; 0];
x0hat = [0; 0; 0; 0 ];
yOL = lsim(sys_OL2, u, t, x0);
yCl = lsim(sys_Cl, u, t, [x0; x0hat]);

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Bharath Maheshwari 2020-12-1

what did ya do?

Johannes James 2021-3-14

It's very bad form to just say "i figured it out" and not exaplin what the solution was. Others coming here following search engine hits, looking for solutions, encounter your useless comment and absence of solution. If you bothered to post, concludet the matter with the solution!

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