Finding first rightmost non-zero column of a matrix?

Question

Teresita Ramirez Aguilar 2019-8-15

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/476202-finding-first-rightmost-non-zero-column-of-a-matrix

评论： Teresita Ramirez Aguilar 2019-8-16

How can I tell MATLAB to find the index of the RIGHTmost non-zero column of said matrix?

I found a similar question and answer for the leftmost column and it worked great! However, I am having trouble finding the rightmost column.

Ex: https://www.mathworks.com/matlabcentral/answers/301099-find-first-non-zero-column-of-a-matrix#answer_232924

I need the leftmost column.

PLS&THANKYOU!

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Teresita Ramirez Aguilar 2019-8-15

I tried looking here https://www.mathworks.com/help/matlab/ref/find.html but nothing I tried is working, new to Matlab..

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

dpb 2019-8-15

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/476202-finding-first-rightmost-non-zero-column-of-a-matrix#answer_387653

编辑：dpb 2019-8-15

在 MATLAB Online 中打开

Same solution as the other except search from the other end...

find(any(A),1,'last')

I think Azzi's solution there doesn't find the column positionally but will find the column with the largest number of nonzero elements in it. So

[2 1
 0 1
 0 1]

with his would return 2, not 1 because three rows of second column return T but only one of column 1 will. But both have nonzero elements.

any() does the logical test by column for there being one or more nonzero elements so doesn't matter how many there are as long is one it'll show up. Then the find() locates either first or last depending on which direction you ask for with the optional argument.

5 个评论
显示 3更早的评论隐藏 3更早的评论

dpb 2019-8-15

编辑：dpb 2019-8-16

在 MATLAB Online 中打开

"find(any(A),1,'last') ... returned a number outside of my column range."

That's not possible with a 2D matrix...something is inconsistent somewhere.

any(A) by default operates on the columns of a 2D array and returns a row vector of length==size(A,2). (*) The last nonzero location in that vector has to be that number or less.

Here's a couple examples...smaller so can see but there's no difference in logic based on size--

>> A=[zeros(5) randn(5)]; A=A(:,randperm(10));
>> A
A =
    0.0662         0   -0.6509    1.2503         0         0    0.0000         0         0    1.1921
    0.6524         0    0.2571    0.9298         0         0   -0.0549         0         0   -1.6118
    0.3271         0   -0.9444    0.2398         0         0    0.9111         0         0   -0.0245
    1.0826         0   -1.3218   -0.6904         0         0    0.5946         0         0   -1.9488
    1.0061         0    0.9248   -0.6516         0         0    0.3502         0         0    1.0205
>> find(any(A),1,'last')
ans =
    10
>> A=A(:,randperm(10));
>> [A;any(A)]
ans =
   -0.6509    1.1921         0         0    0.0000    1.2503         0         0    0.0662         0
    0.2571   -1.6118         0         0   -0.0549    0.9298         0         0    0.6524         0
   -0.9444   -0.0245         0         0    0.9111    0.2398         0         0    0.3271         0
   -1.3218   -1.9488         0         0    0.5946   -0.6904         0         0    1.0826         0
    0.9248    1.0205         0         0    0.3502   -0.6516         0         0    1.0061         0
    1.0000    1.0000         0         0    1.0000    1.0000         0         0    1.0000         0
>> find(any(A),1,'last')
ans =
     9
>>

where the second above also outputs the result of any() as the last line displayed--as noted, it's a logical row vector (converted to double by the concatenation into the array) of the number of columns a A; and is 1 for columns with nonzero elements and zero for those without. Hence, find() on that vector simply cannot return a value outside the range 1:10.

Post your code and the .mat file with the data...

Oh, what does

whos yourArray

return (where "yourArray" is your variable name of this array).

(*) If the 2D array is degenerate and has only one row or column (or, iow, is a vector), then any operates over the non-singleton dimension and will return only a scalar. In that case the result will always be either 1 or empty.

dpb 2019-8-16

I just noticed the "image" tag so that's a possibility...something inconsistent with the assumption matrix meant 2D array :)

Teresita Ramirez Aguilar 2019-8-16

Walter Roberson's answer worked! But I really appreciate everyones help very much !!! :D I apologize for any confusion on my part, I am very new to MATLAB.

请先登录，再进行评论。