Memory overflown for the number to be saved

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Avinash bachu
Avinash bachu 2012-9-10
Hi
I have string like this.
A={'IMSI=208016702935545 CI=20796 LAC=29188'};
I have done this
imsi=regexp(A,'\w*IMSI=\w*','match');
After doing that I get
imsi{1,1}= 'IMSI=208016702935545';
Again I do this to extract the numbe out of it
cellinfo=sscanf(char(imsi{1,1}),'%*5c%d');
But the length of IMSI is too long and is overflown. can anyone suggest something so that I can have cellinfo=208016702935545 ;
Thanks in advance
Avinash
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Oleg Komarov
Oleg Komarov 2012-9-10
Do not double post.
Then what is CI? How do you get it?
Avinash bachu
Avinash bachu 2012-9-10
Sorry, my mistake.
I corrected the question now. Actually, there is no CI. CI was the name given in my code.

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采纳的回答

Jan
Jan 2012-9-10
编辑：Jan 2012-9-10
A = {'IMSI=208016702935545 CI=20796 LAC=29188'};
num = sscanf(A{1}, 'IMSI=%g', 1);
This should actually work, because the 15 digits of the number should be covered by the double precision. Alternatively import it as UINT64:
num = sscanf(A{1}, 'IMSI=%lu', 1);
Obviously the "%d" format saturates at the INT32 limits.
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Avinash bachu
Avinash bachu 2012-9-10
Thanks Jan.
Importing to uint64 didnt work. it was saturated at uint32 using %lu.
Thanks anyway

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更多回答（1 个）

Oleg Komarov
Oleg Komarov 2012-9-10
编辑：Oleg Komarov 2012-9-10
Using the look-behind operator in regular expressions without capturing the token:
cs = regexp(A,'(?<=IMSI=)\d+','match');
str2double(cs{:})
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Avinash bachu
Avinash bachu 2012-9-10
Thanks Oleg. I tried cs = regexp(A,'(?<=IMSI=)\g+','match'); which didnt work. Do you have any other way around. i am very bad at matlab syntax.
Oleg Komarov
Oleg Komarov 2012-9-10
The '\d+' part in the regexp() does not relate to the sscanf() syntax.
cs = regexp(A,'(?<=IMSI=)\d+','match')
The line identifies characters belonging to the set '1234567890'.

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