Index exceeds matrix dimensions
9 次查看(过去 30 天)
显示 更早的评论
Index exceeds matrix dimensions.
Error in tvf_emd (line 47)
y = [fliplr(y(2:2+num_padding-1)) y fliplr(y(end-num_padding:end-1))]; % padding to deal with boundary effect (symmetric).
trying to solve this problem in my code but im finding it difficult. Please can anyone help solve this problem for me. its urgent as I need to complete my paper.
attached are the codes and data used.
回答(2 个)
Walter Roberson
2019-9-17
num_padding = round(length(temp_x)*0.5);% padding number
length is defined as:
temp = size(TheInput)
if any(temp == 0)
length is 0 no matter what the other dimensions are
else
length is max(temp)
end
length is not any particular dimension: for a matrix that is not empty, length is the largest dimension.
You then use effectively go row by row through temp_x, with the rows being length 231, which is less than num_padding, so using num_padding exceeds the end of the row.
7 个评论
Walter Roberson
2019-9-18
I am not clear as to why you removed the for y loop ?
The code does not have enough documentation for me to understand what you want to do.
Did you remove the for y loop in an attempt to vectorize the calculations?
tt=1:numel(y);
ind_remov_pad=num_padding+1:numel(y)-num_paddi
That code is wrong for 2D arrays y.
It looks to me as if the best way to proceed would be to use a for loop whose indices were the row numbers of temp_x, and inside the loop,
y = temp_x(row_number, :);
After which you do the padding and so on.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Image Data Workflows 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!