Conversion to logical from optim.prob​lemdef.Opt​imizationC​onstraint is not possible. Expressing a condition for a parameter.

1 次查看（过去 30 天）
Lenilein
Lenilein 2019-9-17
评论： NN 2021-5-2
Hello,
I am trying to formulate an mixed integer optimization problem and one of my parameters (say A) depends on my optimization variable (say x), which is a binary variable.
I would like that when x=1, A=a and when x=0, A=b;
I realized that I couldn't express it with an "If function" after getting the error Conversion to logical from optim.problemdef.OptimizationConstraint is not possible.
Going through Matlab resources I found solutions using big M constraints for cases where A is expected to be above a superior value when x takes a certain value. However I couldn't find the case where A has to be equal to a specific value.
Can someone help me expressing this condition?
Thank you! :)

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2019-9-17
A = b + x*(a-b)
  2 个评论
NN
NN 2021-5-2
how can i use the same Pbatt which is calculated from optimisation variables depending on its sign in objective function?
Like if Pbatt is positive i have to multiply with cost and if its negative i have to multiply it with another cost .How do i specify Pbatt in objective function accordingly ?
I am also getting the error
Conversion to logical from optim.problemdef.OptimizationConstraint is not possible.
i have used below code.
for i = 1:N
if PbattV == 200
Cost1 = Costa;
elseif PbattV == -200
Cost2 = Costb;
end
end
prob.Objective = dt*Cost1'*PbattV +Cost2'*PbattV;
Kindly help

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Get Started with Optimization Toolbox 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by