Simple fixed-point iteration method
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My task is to implement (simple) fixed-point interation.
So far, I've got the following and I keep receiving error Undefined function 'fixedpoint' for input arguments of type 'function_handle'.
(I'm new in Matlab, so there may be both syntactical or semantical errors...)
function [ x ] = fixedpoint(g,I,y,tol,m)
% input: g, I, y, tol, max
% g - function
% I - interval
% y - starting point
% tol - tolerance (error)
% m - maximal number of iterations
% x - approximate solution
a=I(1);b=I(2);
if(y<a | y>b)
error('The starting iteration does not lie in I.')
end
x=y;
gx=g(y);
while(abs(x-gx)>tol & m>0)
if(gx<a | gx>b)
error('The point g(x) does not lie in I.')
end
y=x;
x=g(y);
m=m-1;
end
采纳的回答
Dimitris Kalogiros
2019-9-22
0 个投票
Dear John
Put your function into the same folder with the program (m-file) that calls it.
4 个评论
John Smith
2019-9-22
Dimitris Kalogiros
2019-9-22
I wonder , what is the calling program.
If you don't mind , could you provide it ?
John Smith
2019-9-23
Dimitris Kalogiros
2019-9-24
Hm hm, I don't know if it is necessary , but I always follow this rule.
更多回答（4 个）
emmanuel john Lavarias
2021-9-27
0 个投票
- Solve one real root of ex−2x−5=0ex−2x−5=0 with x0=−2x0=−2 using the Fixed-Point Iteration Method accurate to four decimal places.
Ahteshamul Hoque Tareq
2022-1-8
0 个投票
a=I(1);b=I(2); if(y<a | y>b) error('The starting iteration does not lie in I.') end x=y; gx=g(y); while(abs(x-gx)>tol & m>0) if(gx<a | gx>b) error('The point g(x) does not lie in I.') end y=x; x=g(y); m=m-1; end
Tsega'ab
2023-12-13
0 个投票
function [ x ] = fixedpoint(g,I,y,tol,m)
% input: g, I, y, tol, max
% g - function
% I - interval
% y - starting point
% tol - tolerance (error)
% m - maximal number of iterations
% x - approximate solution
a=I(1);b=I(2);
if(y<a | y>b)
error('The starting iteration does not lie in I.')
end
x=y;
gx=g(y);
while(abs(x-gx)>tol & m>0)
if(gx<a | gx>b)
error('The point g(x) does not lie in I.')
end
y=x;
x=g(y);
m=m-1;
end
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