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Simple fixed-point iteration method
Solve one real root of ex−2x−5=0ex−2x−5=0 with x0=−2x0=−2 using the Fixed-Point Iteration Method accurate to four decimal places...
Simple fixed-point iteration method
Solve one real root of ex−2x−5=0ex−2x−5=0 with x0=−2x0=−2 using the Fixed-Point Iteration Method accurate to four decimal places...
4 years 前 | 0
