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Question about making a function file with vectors and variables

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Portgas Ace
Portgas Ace 2012-9-20
关闭： MATLAB Answer Bot 2021-8-20
Question deleted by James. Partially restored by Matt Fig:
a part of my program has syntax that looks like this,
for n=1:1:A1 if (Z(n)<3 | Z(n)>9 | Z(n)~=Z(n)) disp('One or more of the element/s is/are not included.'); return;
elseif ~isnumeric(Z(n)) disp('There is error') return; end
so if i enter:
function_name ([3 4 A], [4 5 6])
matlab says: Undefined function or variable 'A'.
  2 个评论
Jan
Jan 2012-9-20
Why do you delete your question? Then the work of the once, who wanted to help you, is lost. Not friendly.
Matt Fig
Matt Fig 2012-9-21
OP:
a part of my program has syntax that looks like this,
for n=1:1:A1 if (Z(n)<3 | Z(n)>9 | Z(n)~=Z(n)) disp('One or more of the element/s is/are not included.'); return;
elseif ~isnumeric(Z(n)) disp('There is error') return; end
so if i enter:
function_name ([3 4 A], [4 5 6])
matlab says: Undefined function or variable 'A'.

此问题已关闭。

回答（4 个）

Wayne King
Wayne King 2012-9-20
编辑：Wayne King 2012-9-20
MATLAB will do that on its own.
>> clear A % in case A is in the workspace
>> a=[1 2 A 4]
The MATLAB error message will be:
Undefined function or variable 'A'.
  1 个评论
Portgas Ace
Portgas Ace 2012-9-20
but im using a function file. im only required to input a vector with only numbers as value and if i entered a non-number, i should show an error. so ex, a = [1 2 A 4]; there should be an error saying ive entered a wrong input. something like that. :(
Wayne King
Wayne King 2012-9-20
If A is not a variable in the workspace, then inputting it into a function will cause an error
function sumout = testfunction(input1 )
sumout = sum(input1);
end
If you call that function with
>>sumout = testfunction([1 2 3 A 4]);
throws an error. You can always use isnumeric() if you want
if ~isnumeric(input)
error( )
end
Jan
Jan 2012-9-20
After A = 1; a = [1,2,A,4]; there is no method to detect, if a has been created using numbers, functions or other variables. When A is e.g. a character array, it is converted to double implicitly:
A = 'Z';
a = [1, 2, A, 4] % ==> [1, 2, 90, 4]
Here A is converted to the type DOUBLE and the ASCII value 90 is stored. Afterwards a is a double vector as all its elements have the same type.
I think, you have a different problem. Perhaps you want to test the class of A before inserting into the vector.
Portgas Ace
Portgas Ace 2012-9-20
a part of my program has syntax that looks like this,
for n=1:1:A1 if (Z(n)<3 | Z(n)>9 | Z(n)~=Z(n)) disp('One or more of the element/s is/are not included.'); return;
elseif ~isnumeric(Z(n)) disp('There is error') return; end
so if i enter:
function_name ([3 4 A], [4 5 6])
matlab says: Undefined function or variable 'A'.

此问题已关闭。

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