How can i fix the error "Error using inline Input must be a character vector." and "Error in (line 9) g=inline(f);"
6 次查看(过去 30 天)
显示 更早的评论
f=exp(2*exp(2)); %I tried this with other functions and it worked
a=0;
b=3;
n=30;
h=(b-a)/n;
g=inline(f);
s=0;
for i=1:n
s=h/2*(g(a+(i-1)*h)+g(a+(i)*h))+s
mensaje=['En la iteracion ',num2str(i),', x es igual a ',num2str(s)];
display(mensaje)
end
0 个评论
回答(1 个)
Walter Roberson
2019-10-21
inline can only be used with character vectors.
Your f is a double precision scalar. If you were to format it into a character vector then would the resulting constant function be something that you would like to apply with an argument Ike you do?
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Function Creation 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!