how to numerically define 1/x^2+0.4/(60-x)^2

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Matthew Aranda Weale
编辑： John D'Errico 2019-11-2
trying to define I= 1/x^2+0.4/(60-x)^2 numerically but says matrix dimensions must agree so incorrect use of /
help

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回答（2 个）

KALYAN ACHARJYA
KALYAN ACHARJYA 2019-11-2
编辑：KALYAN ACHARJYA 2019-11-2
x=10; %define x, here is just an example
I=1/x^2+0.4/(60-x)^2
John D'Errico
John D'Errico 2019-11-2
编辑：John D'Errico 2019-11-2
If x is a vector or array, then you are trying to compute element-wise operations. But / and ^ and * are all operators that are defined in terms of MATRIX multiplies and linear algebra.
Use the ./ .^ and .* operators for element-wise operations.
I= 1./x.^2+0.4./(60-x).^2
Ideas like this would be found in the getting started tutorials for MATLAB. Essenitally, it is always a good idea to read the manual.

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