hello, how can I resolve this?
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2 1 2 1
2 2 4 1
2 3 8 1
2 4 16 1
2 5 32 1
2 6 64 1
2 7 128 1
2 8 256 1
2 9 512 1
2 10 1024 NaN
2 11 2048 NaN
2 12 4096 NaN
hi, suppose that I have the matrix below and (where NaN is a string) how can I calculate the number of NaNs of the fourth column of matrix and assign it to a variable called “N_NAN”? Thank you
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KALYAN ACHARJYA
2019-11-9
编辑：KALYAN ACHARJYA
2019-11-10
data=[2 1 2 1
2 2 4 1
2 3 8 1
2 4 16 1
2 5 32 1
2 6 64 1
2 7 128 1
2 8 256 1
2 9 512 1
2 10 1024 NaN
2 11 2048 NaN
2 12 4096 NaN];
NaN_sum=sum(isnan(data(:,4))); %Its gives the sum of NaN
% Find the r and c of NaN
[r c]=find(isnan(data));
Now replace those r,c with new strings N_NAN, for that you may require to convert the array to cell array, right?
3 个评论
Walter Roberson
2019-11-9
? Why are you doing (isnan(data)==1)==1 ? isnan(data) is the same test as isnan(data)==1 which is the same test as (isnan(data)==1)==1
darova
2019-11-9
I agree. THere is no need fo such overcomplications
KALYAN ACHARJYA
2019-11-10
Yes, its my bad. Thanks for pointing it out @Walter Sir
Thanks @Darova
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