give labels according to string

2019 11 20
1 个回答
回答已采纳
更新时间：2019 11 20
4 次查看（30 天）

0 个投票

I have a cell array of strings with the following pattern
String Label
'Abc\a1\L\XYZ1R08' 1
'Abc\a1\R\XYZ1R09' 1
'Abc\a1\R\XYZ1R10' 1
'Abc\b2\L\XYZ2L01' 2
'Abc\b2\R\XYZ2L02' 2
'Abc\b2\R\XYZ2L03' 2
'Abc\c3\L\XYZ2L04' 3
'Abc\c3\R\XYZ2L05' 3
'Abc\d4\L\XYZ2L06' 4
'Abc\d4\R\XYZ2L07' 4
i wanted to give a new variable, "Label', values according to a1,b2,c3,d4, etc

3 个评论
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Philippe Lebel
Philippe Lebel 2019-11-20
I'm not sure i understood what you wanted but here's my try:
elements = strsplit(my_string,'\');
if strcmp(elements(2),'a1')
Label = 1337;
end
Rik
Rik 2019-11-20
Is that label guaranteed to be between the first two slashes?
Elysi Cochin
Elysi Cochin 2019-11-20
编辑：Elysi Cochin 2019-11-20
yes sir, based on the first two slashes
find the different elements, and give same value for same elements
(a1, b2, c3, d4 - the names can change. This is just an example)
in my example i have 4 different values a1, b2, c3, d4 (it can be greater than 4 also)
So where all i have a1, i want to give 1 , for next value (b2) next value 2 and so on
% its a cell array
my_string = {
'Abc\a1\L\XYZ1R08';
'Abc\a1\R\XYZ1R09';
'Abc\a1\R\XYZ1R10';
'Abc\b2\L\XYZ2L01';
'Abc\b2\R\XYZ2L02';
'Abc\b2\R\XYZ2L03';
'Abc\c3\L\XYZ2L04';
'Abc\c3\R\XYZ2L05';
'Abc\d4\L\XYZ2L06';
'Abc\d4\R\XYZ2L07'};

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 采纳的回答

Star Strider
Star Strider 2019-11-20

2 个投票

Try this:
String = {'Abc\a1\L\XYZ1R08'
'Abc\a1\R\XYZ1R09'
'Abc\a1\R\XYZ1R10'
'Abc\b2\L\XYZ2L01'
'Abc\b2\R\XYZ2L02'
'Abc\b2\R\XYZ2L03'
'Abc\c3\L\XYZ2L04'
'Abc\c3\R\XYZ2L05'
'Abc\d4\L\XYZ2L06'
'Abc\d4\R\XYZ2L07'};
grpstr = regexp(String, '(?<=\\)\w{2}', 'once','match'); % Get Two Letters After First ‘\’
Group = findgroups(grpstr);
Result = {String, Group} % Cell Array
T1 = table(string(String), Group) % Table
producing:
T1 =
10×2 table
Var1 Group
__________________ _____
"Abc\a1\L\XYZ1R08" 1
"Abc\a1\R\XYZ1R09" 1
"Abc\a1\R\XYZ1R10" 1
"Abc\b2\L\XYZ2L01" 2
"Abc\b2\R\XYZ2L02" 2
"Abc\b2\R\XYZ2L03" 2
"Abc\c3\L\XYZ2L04" 3
"Abc\c3\R\XYZ2L05" 3
"Abc\d4\L\XYZ2L06" 4
"Abc\d4\R\XYZ2L07" 4

5 个评论
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Elysi Cochin
Elysi Cochin 2019-11-20
编辑：Elysi Cochin 2019-11-20
it works if string length is 2
but what if the string length between the first 2 slashes not unique
some cases 2 some cases 3
String = {'Abc\a1\L\XYZ1R08'
'Abc\a1\R\XYZ1R09'
'Abc\a1\R\XYZ1R10'
'Abc\bb2\L\XYZ2L01'
'Abc\bb2\R\XYZ2L02'
'Abc\bb2\R\XYZ2L03'
'Abc\c3\L\XYZ2L04'
'Abc\c3\R\XYZ2L05'
'Abc\da4\L\XYZ2L06'
'Abc\da4\R\XYZ2L07'};
what to do if the string between first 2 slashes is as above
Philippe Lebel
Philippe Lebel 2019-11-20
编辑：Philippe Lebel 2019-11-20
replace
grpstr = regexp(String, '(?<=\\)\w{2}', 'once','match'); % Get Two Letters After First ‘\’
by
grpstr = regexp(String, '(?<=\\)\w*', 'once','match'); % Letters After First ‘\’
Star Strider
Star Strider 2019-11-20
One small change in the regexp arguments is all that is needed:
grpstr = regexp(String, '(?<=\\)\w+', 'once','match'); % Get Letters After First ‘\’
Group = findgroups(grpstr)
T2 = table(string(String), Group) % Table
produciing for this version of ‘String’:
T2 =
10×2 table
Var1 Group
___________________ _____
"Abc\a1\L\XYZ1R08" 1
"Abc\a1\R\XYZ1R09" 1
"Abc\a1\R\XYZ1R10" 1
"Abc\bb2\L\XYZ2L01" 2
"Abc\bb2\R\XYZ2L02" 2
"Abc\bb2\R\XYZ2L03" 2
"Abc\c3\L\XYZ2L04" 3
"Abc\c3\R\XYZ2L05" 3
"Abc\da4\L\XYZ2L06" 4
"Abc\da4\R\XYZ2L07" 4
Note that ‘grpstr’ here is:
grpstr =
10×1 cell array
{'a1' }
{'a1' }
{'a1' }
{'bb2'}
{'bb2'}
{'bb2'}
{'c3' }
{'c3' }
{'da4'}
{'da4'}
So with that change, it is robust to changes in the string length between the first two ‘\’.
Star Strider
Star Strider 2019-11-20
As always, my pleasure! (And our pleasure!)

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