Subtracting Vector from a Matrix
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I have the matrix a (8x1001) and b (1x1001) as in attached.
a and b can change in size.
How do I substract b from each row of a and put in a new matrix c?
Thanks.
采纳的回答
Jan
2019-11-21
Matlab can subtract vectors from matrices automatically since R2016b - so called "auto expanding". Do you use an older version? Then:
c = bsxfun(@minus, a, b)
5 个评论
Paul Rogers
2019-11-21
Adam Danz
2019-11-21
I filled in your Matlab release for this question (see the right panel of this page, copied below). In the future when you're writing your question, don't ignore those fields becuase they are super helpful to us and can save everyone a lot of time.
In case anyone's interested, I was curious about the efficiency of bsxfun() so I timed the following 2 lines individually 100,000 times using tic/toc and it turns out that the 2nd line (repmat) is consistently 5-6 times faster (though both are extremely fast).
a and b are the data from the OP's mat files.
c = bsxfun(@minus, a, b);
c = a - repmat(b,size(a,1),1); % 5x faster
Jan
2019-11-21
@Adam: While repmat is (or at least was) an M-function, you can omit the overhead:
c = a - b(ones(1, 8), :);
Good idea, Jan. I would have expected the ones() method to be faster than repmat(), too. But I timed both methods 500000 times and it turns out that the repmat() is actually faster. I repeated this a few times with consistent results. The boxplots below show the results of the 500k reps with outliers removed.
a = repmat((1:8)',1,12);
b = repmat(2,1,12);
% Method 1 (red)
c = a - b(ones(1, 8), :);
% Method 2 (blue)
d = a - repmat(b,size(a,1),1);
And including the outliers
Who knows what's going on in either function (closed source).
更多回答（1 个）
Adam Danz
2019-11-21
"How do I substract b from each row of a and put in a new matrix c?"
As long as the number of columns in b matches the number of columns in a
c = a - b;
Demo:
% Create data
a = repmat((1:8)',1,12);
b = repmat(2,1,12);
c = a - b;
3 个评论
Paul Rogers
2019-11-21
Jan
2019-11-21
Obviously the sizes are not matching. Trust Matlab. See:
size(a)
size(b)
What do you get?
See the 2nd line of my answer:
As long as the number of columns in b matches the number of columns in a
This requirement is met for the data you provided in matrix a and matrix b in your mat files.
load('a.mat')
load('b.mat')
size(a) % 8 1001
size(b) % 1 1001
c = a-b;
size(c) % 8 1001
If that requirement is not met, you cannot perform matrix subtraction without defining how you plan to resolve the size mismatch.
[update]
If your matlab release is prior to r2016a, see Jan's answer which avoids implicit expansion. This is why it's always good to include your matlab release in the field where it is requested while writing your question.
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