Help on understanding the following matlab code ?
1 次查看(过去 30 天)
显示 更早的评论
xt= 15 10 5 0
11 6 1 4
7 2 3 8
3 2 7 12
1 6 11 16
[~,J]=min(flipud(xt),[ ],2)
----------------------------------------------------------
Output J= 1
2
2
3
4
采纳的回答
Jan
2019-11-22
Step by step:
- flipud(xt): This flipps the order of elements vertically. Try it:
x = rand(3,2)
flipud(x)
- min(Y, [ ], 2) : find the minimal value along the 2nd dimension
- [~, J] = ... : Ignore the first output and assing the 2nd output to the variable J
See also:
doc flipud
doc min
0 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Matrices and Arrays 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!