String comparison in table

Question

0 个投票

This is a follow up to my previous question.

t = table({'1', '2'; '2', '3'; '2', '3'; '4', '5'}, [1; 2; 1; 2], 'VariableNames', {'Multico', 'value'})
tochange = strcmp(t.Multico(1, :), '2')

Expected output:

tochange =
  1×2 logical array
   0   1    1

Obtained output:

tochange =
  1×2 logical array
   0   1

I'd like to know why the expected output is not obtained.

Any suggestions on how to obtain the expected output?

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Bhaskar R 2019-11-25

编辑：Bhaskar R 2019-11-25

You are comparing 2 values of the table variable t.Multico row 1 (total 2 elements) to string '2' thats why got only two logical outputs

>> t.Multico(1, :)
    ans =
      1×2 cell array
        {'1'}    {'2'}

Answer 1

AKARSH KUMAR 2020-6-24

0 个投票

The reason is you are not comparing a single value but multiple values in this case two values of the table.

Like in your case t.Multico row 1 (total 2 elements) to string '2' thats why got only two logical outputs