How to replace elements of a matrix with the scaled identity?

1 次查看(过去 30 天)
I have some arbitrary square matrix, for example:
A = [ 1 2 3; 4 5 6; 7 8 9 ];
I would like to replace each element with its scalar value multiplied by the identity of some size n. For example, taking n=2, I want to get:
B = [ 1 0 2 0 3 0;
0 1 0 2 0 3;
4 0 5 0 6 0;
0 4 0 5 0 6;
7 0 8 0 9 0;
0 7 0 8 0 9 ];
Since the size n is constant, the matrix B is guaranteed to have consistent dimensions. Is there a quick way to do this without having to loop over the elements of A and find the corresponding indices of B to place the identity?

采纳的回答

Matt J
Matt J 2019-12-9
B=kron(A,eye(n))
  1 个评论
Shikhar Shah
Shikhar Shah 2019-12-9
This makes a lot of sense. It is useful that I can use any matrix for the second argument of kron(). Thank you so much for your quick and simple answer!

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Logical 的更多信息

产品


版本

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by