Delete specific rows from a cell array and create a new cell array
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Hello Everyone,
I have created a 1x8 cell array from a text file. I want to create a new cell array that will only have a particular feature. If my cell array is "S" then I want to use a condition on S{8}. if any element (n) of S{8} is greater than its next element (n+1) I want to delete the entire row and after deleting all the unwanted rows, I want to create a new cell array with the remaining elements.
For example:
if I have these elements in my cell array "S"
0,0,1,0,0,0,0,10761
0,0,1,0,0,0,0,11067
0,0,1,0,0,0,0,3036687367
0,0,1,0,0,0,0,11271
.
.
0,0,0,0,0,0,0,28509
0,0,0,0,0,0,0,1656057693
0,0,0,0,0,0,0,28713
0,0,0,0,0,0,0,28815
I want to create a new cell array "T" that will only have these elements:
0,0,1,0,0,0,0,10761
0,0,1,0,0,0,0,11067
0,0,1,0,0,0,0,11271
.
.
0,0,0,0,0,0,0,28509
0,0,0,0,0,0,0,28713
0,0,0,0,0,0,0,28815
Any Suggestions?
Thanks.
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回答(1 个)
dpb
2019-12-13
Place where converting the cell array to regular double array makes sense it would seem...there's nothing in the above data that isn't numeric so just use the native double array.
S=cell2mat(S); % convert to double array
ix=[false; (diff(S(:,8))>0)]; % locations of +-ive difference
S(ix,:)=[]; % remove those rows
5 个评论
dpb
2019-12-14
"Here you can see that the code has also skipped some data points (in S{1,8} Row :42 is now Row: 3 in T matrix) and many more."
No, we can't see anything of the sort. What does "the code has skipped some data points" mean? It deleted everything for which diff(S)>0 as per the original specification--that there are duplicated values and therefore a set of points for which the difference is now zero isn't anything that was given as a requirement.
Would have to see all the original data to know; perhaps the condition should be
ix=[false; (diff(T(:,8))>=0)];
but can't tell without a definitive statement of what is the desired result; some heuristic that may work for a given dataset isn't a specification.
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