Why is my circle invisible?

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Jenny Andersen
Jenny Andersen 2019-12-18
评论： Walter Roberson 2019-12-18
I can not figure out why my circle is invisiable when I plot it (It is a regression). Am I missing something? It used to work earlier.
x = [5; 4; -1; 1];
y = [3; 5; 2; 1];
% circle's equation: x^2+y^2 = 2xc1+2yc2+c3
a = [2.*x,2.*y,ones(length(x),1)];
b = [x.^2 + y.^2];
c = a\b;
x_m = c(1)/2;
y_m = c(2)/2;
r = sqrt(x_m^2 + y_m^2 -c(3));
% plot data points
plot(x,y,'o')
hold on
% plot center
plot(x_m,y_m,'+')
% plot circle
circle(x_m,y_m,r)
hold off
  2 个评论
KSSV
KSSV 2019-12-18
For that we should have a look on the function circle.
Jenny Andersen
Jenny Andersen 2019-12-18
It is no function, only an expression.

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采纳的回答

Walter Roberson
Walter Roberson 2019-12-18
编辑：Walter Roberson 2019-12-18
viscircles([x_m, y_m], r)
axis equal
  7 个评论
显示 5更早的评论
Walter Roberson
Walter Roberson 2019-12-18
Which MATLAB release are you using, and do you have the Image Processing Toolbox (that defines viscircles())

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