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Creating table with variable and row names

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Mathias Heuser
Mathias Heuser 2020-1-3
评论： Mathias Heuser 2020-1-3
Hi,
I am having problems with creating a output table, which for some reason work when i only use one variable, but not when i enter a second one. Code:
mean_rgoog = mean(rgoog);
mean_rm = mean(rm);
std_rgoog = std(rgoog);
std_rm = std(rm);
disp(table(mean_rgoog, mean_rm, 'VariableNames', {'mean'}, 'RowNames', ...
{'mean_rgoog', 'mean_rm'}));
Again, it works if i remove the 'mean_rm' from the 'RowNames'. Anybody knows how to fix this, to make it work with multiple rows?
  1 个评论
Adam Danz
Adam Danz 2020-1-3
In the future, provide the entire error message - it gives us very big hints at what the problem is ;)

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采纳的回答

Adam Danz
Adam Danz 2020-1-3
You're likely getting an error,
Error using table
The RowNames property must contain one name for each row in the table.
It appears you're trying to create a table with 1 column and 2 rows but instead, your table() inputs provide two columns of 1 row of data. Instead, vertically concatenate the two rows of data into 1 column.
table([mean_rgoog; mean_rm], 'VariableNames', {'mean'}, 'RowNames', {'mean_rgoog', 'mean_rm'})
  1 个评论
Mathias Heuser
Mathias Heuser 2020-1-3
This worked (makes total sense), i will remember the error in the future - thank you!

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