what is wrong with this code
显示 更早的评论
clc; clear variables;
x(1)=0;
tic
for i=1:500
x(i+1)=(x(i).^2)*0.5+4;
if abs((x(i+1)-x(i)))<=0.00000001
break
else
x(i)=x(i+1);
end
end
toc
采纳的回答
Hiro Yoshino
2020-1-16
if abs((x(i+1)-x(i)))<=0.00000001
This condition is less likely to be met ... I think.
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