what is wrong with this code

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DEV
DEV 2020-1-16
评论： DEV 2020-1-16
clc; clear variables;
x(1)=0;
tic
for i=1:500
x(i+1)=(x(i).^2)*0.5+4;
if abs((x(i+1)-x(i)))<=0.00000001
break
else
x(i)=x(i+1);
end
end
toc

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采纳的回答

Hiro Yoshino
Hiro Yoshino 2020-1-16
if abs((x(i+1)-x(i)))<=0.00000001
This condition is less likely to be met ... I think.
  1 个评论
DEV
DEV 2020-1-16
thank you
I applied
max(abs(x(i+1)-x(i)))<=0.000001
Now it is working

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