solving equation with if statements

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Hello
I am trying to solve the following equation given input time and values (y) vectors.
I tried the following
syms theta kappa alpha
if time < alpha
eqn = exp(-kappa*time)==y;
else
eqn = exp(-kappa)*exp(-theta*(time-alpha))==y;
end
vars = [theta kappa alpha];
S=solve(eqn);
but it raises an error...
Conversion to logical from sym is not possible.
I tried to convert alpha into double (i.e. double(alpha) ) in the if statement but it did not work...
Any suggestions?
the data look like :
Picture1.png

采纳的回答

Walter Roberson
Walter Roberson 2020-1-17
syms theta kappa alpha time y real
eqn = y == piecewise(time < alpha, exp(-kappa*time), exp(-kappa)*exp(-theta*(time-alpha)));
vars = [theta kappa alpha];
S = solve(eqn, kappa, 'returnconditions', true); %solve for which variable ??
  21 个评论
Walter Roberson
Walter Roberson 2020-1-20
Yup, but that gives residue in the range of 62, whereas 5087.59871387777093, 0.00292734523205026836, 803477.437304047635 gives you residue in the range of 39.02 which is significantly better. Given that model, alpha should be large, over 100,000.

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更多回答(2 个)

antoine
antoine 2020-1-18
time and y are vectors (see plot above for data input). all suggestions are welcome.
I can share the data if it helps
thank you ++
  1 个评论
Walter Roberson
Walter Roberson 2020-1-18
Unless time and y are vectors of length 3 exactly, it seems unlikely that there would be any solutions.
It looks to me as if what you have should be a modeling task to estimate parameters rather than a set of simultaneous equations.

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antoine
antoine 2020-1-18
good not know...Not sure I have the skills to do that.
I really appreciated your input and advices.
  1 个评论
antoine
antoine 2020-2-22
dear Walter
Just realized I forgot to thank you for your help
Problem is fixed! I got my equations working.
(I am know stuck with other timer/loop function : see 'time-dependant iteration through a loop?' if you have time...)

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