How to replace the empty cells in a cell array by a 4-bits string?

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Sarah A
Sarah A 2020-1-18
评论： Walter Roberson 2024-11-28
Hello,
How to replace the empty cells " [ ] " in the attached matrix to a 4-bits string we can convert the whole array matrix to double.
For example,
if we have thw following row:
[ '0001', '0101' , '1010', [ ], [ ], [ ], '1111']
it becomes:
[0,0,0,1,0,1,0,1,1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1]

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采纳的回答

Akira Agata
Akira Agata 2020-1-19
How about the following?
load('Key.mat');
idx = cellfun(@isempty,Key); % Find the indexes of empty cell
Key(idx) = {'0000'}; % Replace the empty cells with '0000'
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Thomas Carpenter
Thomas Carpenter 2024-11-28
编辑：Thomas Carpenter 2024-11-28
Using the optimised 'length' operation for cellfun - i.e ~cellfun('length',Key) - is generally more efficient than calling @isempty.
Walter Roberson
Walter Roberson 2024-11-28
Ran in:
Timing test:
Key = num2cell(rand(100,100));
whos Key
Name Size Bytes Class Attributes Key 100x100 1280000 cell
Key(randi(100*100,50,1)) = {[]};
t1 = timeit(@() cellfun(@isempty,Key), 1)
t1 = 0.0055
t2 = timeit(@() ~cellfun('length',Key), 1)
t2 = 8.2372e-05
So the 'length' version is indeed faster.

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更多回答（1 个）

Stephan
Stephan 2020-1-18
编辑：Stephan 2020-1-18
load('Key.mat');
Key1 = Key(:);
Key1 = reshape(replace(string(char(Key1{:}))," ","0000"),size(Key,1),size(Key,2));
results in a string array filing up all empty elements with "0000".

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