How to find the element of a number if that number were to be placed in an ordered list?

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arthurk 2020-2-22

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https://ww2.mathworks.cn/matlabcentral/answers/506954-how-to-find-the-element-of-a-number-if-that-number-were-to-be-placed-in-an-ordered-list

评论： arthurk 2020-2-22

采纳的回答： Stephen23

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For example:

list = (0:10)

number= 2.5

the element it is in-between is 3 and 4

What is the most efficient way of finding where 2.5 would lie in that list and which elements it would be in-between?

Is there a better way than doing a for loop?

for i = 1:length(list)
    if number > list(length(list))
       fprintf('it is greater than any the numbers')
    end
    if number == list(i)
       fprintf('it is element %d',i)
    end
    if number < list(length(list))
        if number > list(i)
            if number < list(i+1)
                fprintf('it is between element %d and %d ',i,i+1 )
            end
        end
    end
end

采纳的回答

Stephen23 2020-2-22

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The robust solution:

>> ida = find(list<number,1,'last')
ida =  3
>> idb = find(list>number,1,'first')
idb =  4

更多回答（1 个）

madhan ravi 2020-2-22

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在 MATLAB Online 中打开

Between = [find(ismember(list1,fix(2.5))), find(ismember(list1,ceil(2.5)))]

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madhan ravi 2020-2-22

Oops thank you for indicating Stephen.

arthurk 2020-2-22

I'm trying to find the most efficient way. As you can see from my code I do have knowledge of using operators, however I'm trying to make it efficiently as possible without expending many lines of code.

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