How to integrate a signal sawtooth?

Question

moustafa abada 2020-3-6

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/509459-how-to-integrate-a-signal-sawtooth

评论： Star Strider 2020-3-6

I'm integrrating the signal sawtooth using the function "integral" such that "0" min limit and "i" is the max limit to get values of theta to plot it with time but there is an error 'Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters.'

Can you help please ?

fs = 1000;
kf=1000;
t = 0:1/fs:2;
signal = @(tt) sawtooth(pi*2*tt+pi);
theta=[];
for i = (0:1/fs:2)
theta=2*pi*kf*integral(signal,0,i);
end
plot(t,theta[i])

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Answer 1

Star Strider 2020-3-6

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/509459-how-to-integrate-a-signal-sawtooth#answer_418916

在 MATLAB Online 中打开

Try this:

fs = 1000;
kf=1000;
t = 0:1/fs:2;
signal = @(tt) sawtooth(pi*2*tt+pi);
theta=zeros(size(t));
for i = 1:numel(t)
    theta(i)=integral(signal,0,t(i));
end
figure
plot(t,theta)