why isnt the function tf working
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why isnt the function tf working?
i keep getting error message
6 个评论
Star Strider
2020-3-20
Post the error message.
Type this:
ver control
in your Command Window and copy and paste the output to a Comment here.
Minh-Buu Nguyen
2020-3-20
编辑：Jan
2020-11-30
Ameer Hamza
2020-3-20
Minh-Buu, you don't have Control System Toolbox installed. You need this toolbox to use tf().
Minh-Buu Nguyen
2020-3-22
Star Strider
2020-3-22
That depends on the type of license you have.
What sort of license do you have? Are you using MATLAB as part of a university license or a personal license?
lounis chehrit
2021-6-10
Just a question is It normal to have a transfer function like this ?
It's definied by :
Real(TF(v)) = cos(2*pi*v).
and phase is 0.
I thing that the parameter s=j*w.
So is It normal to have a real part like this? ( parameter in the cosine)
and how to get transfert function from real and image parts.
回答（1 个）
Samatha Aleti
2020-3-27
5 个投票
Hi,
If you have the licensed product “Control Systems Toolbox”, but have not installed yet, you can do as follows:
- Go to MATLAB - > HOME -> Add-Ons -> Get Add-ons -> search for “Control Systems Toolbox” -> click Install
If you do not have the product, then
- you can download the trial version for “Control Systems Toolbox” using this link:https://www.mathworks.com/products/control.html
- Check the Pricing and Licensing details here to purchase
For any support regarding purchase or License contact the sales team:
4 个评论
Laurent Prea
2020-11-8
Thanks. I was looking for the toolbox :)
Goar Ayrapetyan
2020-11-30
Thank you so much!
Josue Huerta
2021-3-23
This really helped! Thank you!
lounis chehrit
2021-6-10
Just a question is It normal to have a transfer function like this ?
It's definied by :
Real(TF(v)) = cos(2*pi*v).
and phase is 0.
I thing that the parameter s=j*w.
So is It normal to have a real part like this? ( parameter in the cosine)
and how to get transfert function from real and image parts.
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2020-3-20
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