Matrix dimensions must agree

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Hi, I'm trying to plot a field, but it always shows me the next error:
Matrix dimensions must agree.
Error in codeH (line 24)
Hx = (((1j .* k .* a.^2 .* I0 .* cos(theta)) ./ (x.^2+(z-b).^2)) .* (1 + 1 ./ (1j .*
k .* sqrt(x.^2+(z-b).^2))) .* exp(-1j .* k .* sqrt(x.^2+(z-b).^2))) .*
sin(theta).*cos(phi);
The code that I'm using is this:
clear all
close all
clc
a = 0.4;
f = 10^6;
w = 2 .* pi .* f;
I0 = 1;
b = (0.4/2);
mu0 = 4 * pi * 1e-7;
e0 = 8.85e-12;
k = w .* sqrt( mu0 .* e0 );
theta = (-pi/2:pi/3:pi/2);
phi = (0:pi/2:2*pi);
xx = linspace(-1,0.1,1);
zz = xx;
[x,z] = meshgrid(xx,zz);
Hx = (((1j .* k .* a.^2 .* I0 .* cos(theta)) ./ (x.^2+(z-b).^2)) .* (1 + 1 ./ (1j .* k .* sqrt(x.^2+(z-b).^2))) .* exp(-1j .* k .* sqrt(x.^2+(z-b).^2))) .* sin(theta).*cos(phi);
Hz = (((1j .* k .* a.^2 .* I0 .* cos(theta)) ./ (x.^2+(z-b).^2)) .* (1 + 1 ./ (1j .* k .* sqrt(x.^2+(z-b).^2))) .* exp(-1j .* k .* sqrt(x.^2+(z-b).^2))) .* cos(theta);
quiver(x,z,abs(Hx),abs(Hz))
I'm kind of desperate right now

采纳的回答

David Hill
David Hill 2020-3-31
Several problems I have noticed:
a = 0.4;
f = 10^6;
w = 2*pi*f;%scalar no need for .
I0 = 1;
b = (0.4/2);
mu0 = 4 * pi * 1e-7;
e0 = 8.85e-12;
k = w*sqrt(mu0*e0);%scalar no need for .
theta = linspace(-pi/2,pi/2,100);%this must be a consistent size based on your equation, use linspace
phi = linspace(0:2*pi,100);%consistent size
xx = linspace(-1,1,100);%not sure what you are doing here but size is only 1
zz = xx;
[x,z] = meshgrid(xx,zz);%this is now a 100x100 matrix
for k=1:100%you have to keep the size consistent
Hx(k,:) = (((1j .* k .* a.^2 .* I0 .* cos(theta)) ./ (x.^2+(z(k,:)-b(k,:)).^2)) .* (1 + 1 ./ (1j .* k .* sqrt(x.^2+(z(k,:)-b(k,:)).^2))) .* exp(-1j .* k .* sqrt(x.^2+(z(k,:)-b(k,:)).^2))) .* sin(theta).*cos(phi);
Hz(k,:) = (((1j .* k .* a.^2 .* I0 .* cos(theta)) ./ (x.^2+(z(k,:)-b(k,:)).^2)) .* (1 + 1 ./ (1j .* k .* sqrt(x.^2+(z(k,:)-b(k,:)).^2))) .* exp(-1j .* k .* sqrt(x.^2+(z(k,:)-b(k,:)).^2))) .* cos(theta);
end
quiver(x,z,abs(Hx),abs(Hz))
I'm not sure if everyting is now correct, but you get the idea.

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