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please help me, how do I make the code for the equation in the following picture?

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Muhammad Rohim
Muhammad Rohim 2020-4-17
关闭： MATLAB Answer Bot 2021-8-20
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Peter O
Peter O 2020-4-17
You can't code an infinite sum exactly, but fortunately, this one is bounded (x^2 on the denominator and the numerator is bounded between -1 and 1).
Pick a big n:
n_max=100;
ns = 1:n_max;
sum_n = cumsum( sin(2*ns)./ns.^2);
plot(ns, sum_n)
You will see it very quickly converges, after 20 terms or so.
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