Problem with answer 15.2 Creating and Calling Functions: (4/6) Create and Call a Function, task 1 MATLAB Fundamentals

Question

Gareth George 2020-5-4

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评论： Lester 2023-10-9

采纳的回答： Geoff Hayes

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The problem asks us to modify the function call using two inputs. I put the answer as follows:

top5 = getLargestN(x,5)

i get a message 'error using exercise>getLargestN too many input arguments'.

The answer i solution is identical to one I gave. How do I move forward here?

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Answer 1

Geoff Hayes 2020-5-5

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Gareth - did you update the function signature as well so that it accepts two inputs? Presumably you have defined the function (with body) like

function [res] = getLargestN(x)

and you would need to change this to

function [res] = getLargestN(x,y)
% do something in code with y

so that the signature matches how you are calling it (when you pass in the x and 5).

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Geoff Hayes 2020-5-5

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Gareth - I would first try to get the function returning the correct response (I don't understand either what "check that x is not modified" means). So right now your function is

function Y= getLargestN(x,5)
    top5=Y
end

There are a couple of problems. The signature defines the output parameter and the input parameters. These parameters are variables and since 5 is not a variable (but a value) you cannot define it as a parameter. (You can pass 5 into this function when you call it.) So change this to something like

function Y = getLargestN(x, numElements)

Try to name the variables as to their purpose. Next, the output parameter is Y but is not set anywhere in your code. In fact, you are trying to use it before it has been defined. (I think the top5 variable is meant to be the output from this function when you call it...and not a variable within the function because you don't know how many elements you will be asked to extract.

function Y = getLargestN(x, numElements)
    Y = ...;
end

Now you just have to sort the data.

Gareth George 2020-5-6

Thanks Geoff! I got there in the end. Really helpful. I've been used to doing these tasks one at a time, so didn't anticipate having to edit code in a window further down first :)

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Answer 2

Sanket 2022-11-4

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y0 = 0.4;

yline(y0)

tzerox = findcrossing(t,x-y0)

tzeroy = findcrossing(t,y-y0)

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Answer 3

Bhavesh Pawar 2022-3-11

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y0 = 0.4;
yline(y0)
tzerox = findcrossing(t,x,y0)
tzeroy = findcrossing(t,y,y0)

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Enes Çelik 2022-12-1

Thank you so much Oguz!

Lester 2023-10-9

Thank you, the code helped me.!

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Answer 4

Joed Blair Jacalan 2023-8-12

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Modify the definition of the findcrossing function so that it takes a third input z.
Add a new line to the beginning of the function:y = y - z;
In the Task 1 section of the script, change the value of y0 to 0.4.
Modify the two calls to findcrossing to add y0 as an input.