problem with automized add_block destinations
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hello,
I am using the add_block function to automatize the creation of a model in simulink. I have stored the block names in a column of a table data, i would like to add the blocks and automatically change their names according to the string data of the table. Here is the code:
nL = numel(data.X)
for i=1:nl
h=add_block('MyLibrary/BlockName' , ['MyModel/',data.Names(i)])
end
here is the error message:
"Invalid destination block specification."
data.Names is a string column of the table data. I have tried using another column of the table
for i=1:nl
h=add_block('MyLibrary/BlockName' , ['MyModel/',num2str(data.X(i))])
end
and this works perfectly! What i am missing? please help! Thank you all!
4 个评论
Ameer Hamza
2020-5-8
编辑：Ameer Hamza
2020-5-8
Can you paste the output of
data.Names(1)
Davide Maglione
2020-5-8
Sulaymon Eshkabilov
2020-5-8
you are accessing to your stored created block names in strings via their index numbers. That is it.
Davide Maglione
2020-5-8
采纳的回答
Ameer Hamza
2020-5-8
编辑：Ameer Hamza
2020-5-8
Change the line to this
h=add_block('MyLibrary/BlockName' , ['MyModel/',char(data.Names(i))])
%^ add char here
6 个评论
Davide Maglione
2020-5-8
Ameer Hamza
2020-5-8
I am glad to be of help.
The actual reason is that you were trying to use char() and string() datatype in the same vector. These are distinct data types in MATLAB and not interchangeable. The code in answer makes both variables of type 'char', which corrects the issue.
Davide Maglione
2020-5-9
Ameer Hamza
2020-5-9
The name is a bit misleading, but there is a good reason. Traditionally, MATLAB only used 'char' data type, and the terms char array and strings were used interchangeably. However, from R2016b, MATLAB officially introduced "string" data type. The function num2str existed since R2006a, and it outputs a char array. Historically the name num2str makes sense. But after the introduction of a separate "string" data type, this becomes a bit misleading. To maintain backward compatibility, the function still output char array.
Davide Maglione
2020-5-9
Ameer Hamza
2020-5-9
I am glad to be of help.
更多回答（1 个）
Sulaymon Eshkabilov
2020-5-8
0 个投票
you are accessing to your stored created block names in strings via their index numbers. That is it.
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