Matlab app designer confuses the end written inside matrix index with the end for if and for loop

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Hi all
I got a piece of my code that is causing function nesting error and the root cause is that matlab is not understanding the end written in Matrix(end)
is not related to the loop or function end and has messed up
exactly where I haveTtot(end) , this end is confused
for fn=1:numel(files)
ff= xlsread(strcat(files{fn},'.xlsx'));
filename=files{fn};
t = ff(:,1);
resol=t(2)-t(1);
motion6t=ff;
mulnames=readcell('Ms.xlsx')
mask = strcmp(filename, mulnames(:,1));
multip = cell2mat(mulnames(mask, 2));
resol=t(2)-t(1)
if fn==1
motiontot=[];
for m=1:multip
if m==1
Ttot=t.';
else
Ttot= [Ttot,t.'+Ttot(end)+resol];
end
end
else
for m=1:multip
Ttot= [Ttot,t.'+Ttot(end)+resol];
end
end
for m=1:multip
motiontot=[motiontot;motion6t];
end
end
  11 个评论
farzad
farzad 2020-5-13
Dear Walter, I checked, and it seems that whenever I remove this block , the whole code is ok. the only suspicious ' sign, was t.' in the summation equation with Ttot. but when I removed it, I still have the same error. I had some variables with the warning : the variable spans among more functions. I resolved it as well, but still I have the same problem :
for fn=1:numel(files)
ff= xlsread(strcat(files{fn},'.xlsx'));
fname=files{fn};
t = ff(:,1);
resol=t(2)-t(1);
motion6t=ff;
cd(myperc)
mulnames=readcell('Multipliers.xlsx');
mask = strcmp(fname, mulnames(:,1));
mu = cell2mat(mulnames(mask, 2));
resol=t(2)-t(1);
if fn==1
motiontot=[];
for m=1:mu
if m==1
mTtot=t;
else
mTtot= [mTtot ,t.'+mTtot(end)+resol];
end
end
else
for m=1:mu
mTtot= [mTtot ,t.'+mTtot(end)+resol];
end
end
for m=1:mu
motiontot=[motiontot;motion6t];
end
farzad
farzad 2020-5-13
编辑:farzad 2020-5-13
Ok this is the complete code, and trying this on workspace I get error on mTtot:
Array indices must be positive integers or logical values.
Error in test (line 47)
mTtot= [mTtot ,t.'+mTtot(end)+resol];
mydir=uigetdir()
content = dir('*.xlsx');
content([content.isdir]) = []; % remove directories
files = cell(size(content));
% Extract the filename without the extentions
for fi = 1:numel(files)
[~, files{fi}] = fileparts(content(fi).name);
end
for fn=1:numel(files)
ff= xlsread(strcat(files{fn},'.xlsx'));
fname=files{fn};
t = ff(:,1);
resol=t(2)-t(1);
motion6t=ff;
mulnames=readcell('Ms.xlsx');
mask = strcmp(fname, ulnames(:,1));
mu = cell2mat(mulnames(mask, 2));
mTtot=[];
resol=t(2)-t(1);
if fn==1
motiontot=[];
for m=1:mu
if m==1
mTtot=t;
else
mTtot= [mTtot ,t.'+mTtot(end)+resol];
end
end
else
for m=1:mu
mTtot= [mTtot ,t.'+mTtot(end)+resol];
end
end
for m=1:mu
motiontot=[motiontot;motion6t];
end
maxlim=max(max(motion6t(:,2:7)));
minlim=min(min(motion6t(:,2:7)));
directory=pwd;
end

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采纳的回答

Walter Roberson
Walter Roberson 2020-5-13
mTtot=[]
size(mTtot)
mTtot =
[]
ans =
0 0
with it being empty, end as an index would be 0. mTtot(end) would be mTtot(0) which is not permitted.
mTtot= [mTtot ,t.'+mTtot(end)+resol];
Perhaps you are wanting mTtot(end) to be empty instead of an error when mTtot is empty. But if that were the case, then you would have the situation
mTtot = [[], t.'+[]+resol]
and anything + [] is [], so you would be dealing with
mTtot = [[], []]
which would leave mTtot empy, but I suspect you are trying to append to it in that statement,.
  16 个评论

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