How can I make variable value instead of constant one?
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a = 1.27; b = 0.19 ; c = 0.44 ; d = 0.2 ; e = 300 ; f = 5*10^21 ; g = 2*10^23 ; h = 1.2 ; i = 8.61733*10^(-5); j = 2*10^21; k1 = 0.1 ; B1 = 0.045 ;
x = linspace(0, 1.7);
A1 = j.*(f/g).^((i.*e)/(4*B1)).*((2*B1.^2)/((2*B1)-(i.*e))).*exp(-(1/(2*B1)).*(a-k1-((b.^2)/(4*B1))));
D1 = (1/sqrt(2*b.^2*pi)).*exp(-(x+((b.^2)/(2*B1))-a).^2/(2*b.^2));
C1 = (2*exp((h-x)/(i.*e)))/(1+2*exp((h-x)/(i.*e))+exp(((2*h)-(2*x)-d)/(i.*e)));
E1 = A1.*((2/C1).^((i*e)/(2*B1)))*D1 ;
E1 = linspace(10^10, 10^19);
D0 = linspace(10^10, 10^19);
D0 = C1*E1;
xlabel('x'), ylabel ('y'),plot(x,D0,'r')
I should obtain parabola graph with y range from 10^10 to 10^19, but I got several 10^3 in y-axis. So I found out C1 showed constant value instead of variable figure as x ranges from 0 to 1.7.
How can I fix this problem?
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KALYAN ACHARJYA
2020-6-1
编辑:KALYAN ACHARJYA
2020-6-1
C1 = ((2*exp(h-x)/(i.*e))/(1+2*exp(h-x))/(i.*e))+exp(((2*h)-(2*x)-d)/(i.*e));
The code mesh with multiple / sign, please assign to specific part with () bracket, so that it can be readable easily to dedug the code.
采纳的回答
Ameer Hamza
2020-6-1
编辑:Ameer Hamza
2020-6-1
You need to use element-wise operators
a = 1.27; b = 0.19 ; c = 0.44 ; d = 0.2 ; e = 300 ; f = 5*10^21 ; g = 2*10^23 ; h = 1.2 ; i = 8.61733*10^(-5); j = 2*10^21; k1 = 0.1 ; B1 = 0.045 ;
x = linspace(0, 1.7);
A1 = j.*(f/g).^((i.*e)/(4*B1)).*((2*B1.^2)./((2*B1)-(i.*e))).*exp(-(1/(2*B1)).*(a-k1-((b.^2)./(4*B1))));
D1 = (1./sqrt(2*b.^2*pi)).*exp(-(x+((b.^2)./(2*B1))-a).^2./(2*b.^2));
C1 = (2*exp((h-x)./(i.*e)))./(1+2*exp((h-x)./(i.*e))+exp(((2*h)-(2*x)-d)./(i.*e)));
E1 = A1.*((2./C1).^((i.*e)./(2*B1))).*D1 ;
xlabel('Energie (eV)'), ylabel ('la densite des etats profonds (cm^-3/eV)'),plot(x,C1,'r')
Plot for C1:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/307675/image.png)
更多回答(1 个)
Drishti Jain
2020-6-1
You can use a 'for' loop.
for z=1:100
C1(z) = (2*exp((h-x(z))/(i.*e)))/(1+2*exp((h-x(z))/(i.*e))+exp(((2*h)-(2*x(z))-d)/(i.*e)));
end
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