How can i run 2 for loops at the same time?

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Petros Mata
Petros Mata 2020-6-6
编辑： the cyclist 2020-6-6
My problem with the code below is that i can't run the two for loops at the same time.I want to check for j=1 and p=1 which of the if conditions is true and do the actions,then check for j=2 and p=4 etc.But the way it is right now , it will check for j=1 and for every p possible untill it changes for j=2.
Any help will be much appreciated
function z=coder(y,d)
ymin=min(y);
Number_samples=length(y);
z=zeros(1,Number_samples*3);
for j=1:Number_samples
for p=1:3:Number_samples*3-2
if y(j)==ymin
z(1,p)=0;
z(1,p+1)=0;
z(1,p+2)=0;
elseif y(j)==ymin+d
z(1,p)=0;
z(1,p+1)=0;
z(1,p+2)=1;
elseif y(j)==ymin+2*d
z(1,p)=0;
z(1,p+1)=1;
z(1,p+2)=0;
elseif y(j)==ymin+3*d
z(1,p)=0;
z(1,p+1)=1;
z(1,p+2)=1;
elseif y(j)==ymin+4*d
z(1,p)=1;
z(1,p+1)=0;
z(1,p+2)=0;
elseif y(j)==ymin+5*d
z(1,p)=1;
z(1,p+1)=0;
z(1,p+2)=1;
elseif y(j)==ymin+6*d
z(1,p)=1;
z(1,p+1)=1;
z(1,p+2)=0;
end
end
end
end
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Petros Mata
Petros Mata 2020-6-6
I want it to be:
(1,1)
(2,4)
(3,7)
(4,10)
etc.
If i use only one loop , lets say for j=1:Number_samples, i will have to change z(1,p) , z(1,p+1) , z(1,p+2) to z(1,j) , z(1,j+1) , z(1,j+2) for every if condition.Then for j=1 , i will see which if condition is true for y(1) and i will have a result to the z(1,1) , z(1,2) , z(1,3) , but then when j=2 i will put the next results to z(1,2) , z(1,3) , z(1,4) which two of them i already have. I used the two loops hoping that firstly it will check for j=1, which of the y(1) conditions is correct then for p=1 put z(1,1) , z(1,2) and z(1,3) and after that for j=2 , which of the y(2) conditions is correct then for p=4 put z(1,4),z(1,5),z(1,6) etc.
I hope what I'm trying to say is clear enough.
Image Analyst
Image Analyst 2020-6-6
When you say at the "same time" do you mean like in parallel, like with "parfor" in the Parallel Processing Toolbox?

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回答（1 个）

the cyclist
the cyclist 2020-6-6
编辑：the cyclist 2020-6-6
From your reply to my comment, it seems to me that you really do only need one for loop. Instead of your
for j=1:Number_samples
for p=1:3:Number_samples*3-2
if y(j)==ymin
...
you instead just need
for j=1:Number_samples
p = j+3; % No for loop here. Just need p to be j+3 in each j-loop
if y(j)==ymin
...
That will give the (i,j) pattern
(1,1)
(2,4)
(3,7)
(4,10)

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