Randi with string variables

2012 11 21
3 个回答
8 次查看（30 天）

0 个投票

Goodmorning everybody,
I'm trying to use the 'randi' function on Matlab (but this is for a script on Psychtoolbox). I would like to present a string value, instead of a numerical value. This is what I obtain :
First trial :
>> items = {'lapin', 'souris', 'voiture', 'saumon', 'vÈlo', 'table', 'cochon'};
>> randi(items{i});
*?? Subscript indices must either be real positive integers or logicals.>>*
Second trial :
>> items = {'lapin', 'souris', 'voiture', 'saumon', 'vÈlo', 'table', 'cochon'};
>> randi(items);
*??? Error using ==> randi
Inputs must be numeric.*
Third trial :
>> items = {'lapin', 'souris', 'voiture', 'saumon', 'vÈlo', 'table', 'cochon'};
>> randi(7)
ans =
4
How Matlab can show me the string values specified in 'items' with randi?
Thanks!!
-Emilie

请先登录，再回答此问题。

回答（3 个）

Azzi Abdelmalek
Azzi Abdelmalek 2012-11-21
编辑：Azzi Abdelmalek 2012-11-21

1 个投票

items = {'lapin', 'souris', 'voiture', 'saumon', 'vÈlo', 'table', 'cochon'}
n=numel(items);
out=items(randi(n,n,1))
If you want to avoid repetition use
n=numel(items);
items(randperm(n))

2 个评论
显示 无 隐藏 无

Emilie04
Emilie04 2012-11-21
Thank you :) That functions.
But I want to go father. I want that Matlab choses 1 value in the list, randomly and after its choice, it continues to read the list in the order defined in items = {'lapin', 'souris', 'voiture', 'saumon', 'vÈlo', 'table', 'cochon'};
For example : it choses, randomly 'saumon', and then it presents 'vélo' 'table', 'cochon'
Two problems : with this method, it always choses more than one items (and if I write randperm(1:7), that doesn't function).
>> items = {'lapin', 'souris', 'voiture', 'saumon', 'vÈlo', 'table', 'cochon'}; >> n=numel(items); >> SP=items(randperm(3))
StartPosition =
'souris' 'voiture' 'lapin'
>> PositionOrder=[StartPosition:7 1:(StartPosition-1)] ??? Undefined function or method 'colon' for input arguments of type 'cell'.
Thanks !
Jan
Jan 2012-11-21
@Emilie: The error message means, that "StartPosition" is a cell. It seems like you have confused the StartPosition, which is most likely an index, with the index contents.
Do not use randperm(1:7) but randperm(7).

请先登录，再进行评论。

Jan
Jan 2012-11-21
编辑：Jan 2012-11-21

1 个投票

I suggest to read the Getting Started chapters of Matlab. The documentation of randi (see "help randi", "doc randi") explain, that a number is replied and which inputs are needed. Then it is obvious that "randi(items)" must fail und you do not have to ask the forum for this.
items = {'lapin', 'souris', 'voiture', 'saumon', 'vÈlo', 'table', 'cochon'};
n = numel(items);
index = randi(n, 1);
selectedItems = items(index:n)
You see: "items" are your data, while "randi" and "index" are indicies only. To get the wanted indices, the actual data do not matter at all, therefore the creation of "index" does not require the contents of "item", but only its size.
Daniel Shub
Daniel Shub 2012-11-21

1 个投票

Is this what you want?
items = {'lapin', 'souris', 'voiture', 'saumon', 'vÈlo', 'table', 'cochon'};
items(randi(length(items)):end)

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Emilie04
Emilie04 2012-11-21
Oh Yes thank you!!!! Two days on this function.
Tanks a lot :):)

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Image display and manipulation 的更多信息

标签

提问:

Emilie04
Emilie04
2012-11-21

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by