matrix dimension mismatch problem

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Debasish Mishra
Debasish Mishra 2020-6-27
评论： Star Strider 2020-6-27
hiii
i have an issue of matrix dimension mismatch..i have this following code.
R=1:1:500;
d=[1 2 3 4];
delB=1;
Bmn=1;
a=1+((delB*d)-(Bmn*d./Rb)).^2;
b=1+(delB*d).^2-(Bmn*d./Rb).^2;
c=1+((delB*d)+(Bmn*d./Rb)).^2;
hmn=1.414*kpqt^2*d*((1./(sqrt(a.*(b+sqrt(a.*c)))))+(1./(sqrt(c.*(b+sqrt(a.*c))))));
XT=tanh(hmn*L);
This is showing matrix dimention mismatch.
plz help me out..
thank u in advance.

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回答（2 个）

madhan ravi
madhan ravi 2020-6-27
d = (1:4).';
Star Strider
Star Strider 2020-6-27
The assignment to ‘Rb’ appears to be missing. Since you are using element-wise division wih it, it appears to be a vector, so I created it as a random (1x4) vector to match ‘d’. (Also, ‘kpqt’ and ‘L’ are missing, although they appear to be a scalars.)
Assuming that ‘Rb’ is also a (1x4) vector, do element-wise multiplication:
hmn=1.414*kpqt^2*d.*((1./(sqrt(a.*(b+sqrt(a.*c)))))+(1./(sqrt(c.*(b+sqrt(a.*c))))));
↑ ← HERE
If the undefined variables have different row and column sizes than I assumed here, my Answer may need to change.
  2 个评论
Debasish Mishra
Debasish Mishra 2020-6-27
thanx for responding.actually i wrote Rb to be R by mistake.R and Rb both are same.
Star Strider
Star Strider 2020-6-27
My pleasure!
In that situation, you also need to transpose either ‘d’ or ‘R’ (although not both).
My original Answer remains valid with those changes, since that multiplication needs to be element-wise either way.
.

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