compressing a code, help me
显示 更早的评论
Any one knows how to compress this code as much as possible?
for VetorN = fix((20*sqrt(2).^(0:5)))
[row,col] = size(VetorN);
i = (1: col);
discSt.N = VetorN(i);
VN = VetorN;
CD0 = VetorN *3;
if VetorN == 20
CD01 = CD0;
elseif VetorN == 28
CD02 = CD0;
elseif VetorN == 40
CD03 = CD0;
elseif VetorN == 56
CD04 = CD0;
else
CD05 = CD0;
end
pause()
end
MCD0 = [CD01 CD02 CD03 CD04 CD05]
采纳的回答
madhan ravi
2020-7-2
VetorN = fix( (20 * sqrt(2) .^ (0 : 5) ) )
MD0 = VetorN * 3;
MD0(end - 1) = [ ]
4 个评论
Cauli Vilela Ferreira
2020-7-2
madhan ravi
2020-7-2
VetorN = fix( (20 * sqrt(2) .^ (0 : 5) ) );
MD0 = zeros(1, numel(VectorN);
for k = 1 : numel(VetorN)
MD0(k) = VetorN(k) * 3;
end
MD0(end - 1) = [ ]
Cauli Vilela Ferreira
2020-7-2
madhan ravi
2020-7-2
So remove the last line in my code ;)
更多回答（1 个）
Image Analyst
2020-7-2
Not sure why it needs to be compressed as much as possible, but this will compress it as much as possible while giving the very same output:
MCD0=[60,84,120,168,339]
This assumes that after that you no longer need the component variables CD01, CD02, CD03, CD04, CD05, and CD06. If you still need those variables for some reason, then of course you'll need to compute them.
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