compressing a code, help me

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Cauli Vilela Ferreira
回答： Image Analyst 2020-7-2
Any one knows how to compress this code as much as possible?
for VetorN = fix((20*sqrt(2).^(0:5)))
[row,col] = size(VetorN);
i = (1: col);
discSt.N = VetorN(i);
VN = VetorN;
CD0 = VetorN *3;
if VetorN == 20
CD01 = CD0;
elseif VetorN == 28
CD02 = CD0;
elseif VetorN == 40
CD03 = CD0;
elseif VetorN == 56
CD04 = CD0;
else
CD05 = CD0;
end
pause()
end
MCD0 = [CD01 CD02 CD03 CD04 CD05]

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采纳的回答

madhan ravi
madhan ravi 2020-7-2
VetorN = fix( (20 * sqrt(2) .^ (0 : 5) ) )
MD0 = VetorN * 3;
MD0(end - 1) = [ ]
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Cauli Vilela Ferreira
Cauli Vilela Ferreira 2020-7-2
How cant i add VetorN(1,5), i forgot to put in the code
for VetorN = fix((20*sqrt(2).^(0:5)))
[row,col] = size(VetorN);
i = (1: col);
discSt.N = VetorN(i);
VN = VetorN;
CD0 = VetorN *3;
if VetorN == 20
CD01 = CD0;
elseif VetorN == 28
CD02 = CD0;
elseif VetorN == 40
CD03 = CD0;
elseif VetorN == 56
CD04 = CD0;
elseif VetorN== 80
CD05 = CD0;
else
CD06 = CD0;
end
pause()
end
MCD0 = [CD01 CD02 CD03 CD04 CD05 CD06]
madhan ravi
madhan ravi 2020-7-2
So remove the last line in my code ;)

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更多回答（1 个）

Image Analyst
Image Analyst 2020-7-2
Not sure why it needs to be compressed as much as possible, but this will compress it as much as possible while giving the very same output:
MCD0=[60,84,120,168,339]
This assumes that after that you no longer need the component variables CD01, CD02, CD03, CD04, CD05, and CD06. If you still need those variables for some reason, then of course you'll need to compute them.

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