How to plot a piecewise defined function?
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Hi
I want to plot a piecewise defined function. My Problem is, that the plot isn't right and I don't find the mistake... would be great, if somebody could help me!
function CubicSpline
clear all;
clc;
close all;
%CatmullRom:
B1=0;
C1=1/2;
x=-2:.01:2;
y1=zeros(size(x));
if abs(x)< 1,
y1=1/6*((12-(9*B1)-(6*C1))*abs(x).^3 +(-18+(12*B1)+(6*C1))*abs(x).^2 + (6-(2*B1)));
elseif 1 <= abs(x) < 2
y1 = 1/6*(((-B1-6*C1)*abs(x).^3 + (6*B1+30*C1)*abs(x).^2 + (-12*B1-48*C1)*abs(x)+(8*B1+24*C1)));
else y1 = 0;
end
figure(1);clf; hold on;
plot(x,y1,'r')%,x, y2, 'b', x, y3, 'g'
xlabel('X-Axis')
ylabel('Function values')
grid on;
legend({'CatmullRom: B = 0, C = 1/2'},'Location','EastOutside')
5 个评论
Azzi Abdelmalek
2012-12-6
Your program is working, what is the expected result?
Jan
2012-12-6
It is a waste of time to remove all loaded function after starting this function by "clear all". This does not even clean the local workspace, because there are no variables declared before.
Simon
2012-12-6
Simon
2012-12-7
回答(1 个)
Andrei Bobrov
2012-12-6
编辑:Andrei Bobrov
2012-12-6
B1=0;
C1=1/2;
x0 = -2:.1:2;
x=abs(x0);
y1=zeros(size(x));
t = [x < 1, x >= 1 & x < 2];
y1(t(:,1)) = 1/6*((12-(9*B1)-(6*C1))*x(t(:,1)).^3 +...
(-18+(12*B1)+(6*C1))*x(t(:,1)).^2 + (6-(2*B1)));
y1(t(:,2)) = 1/6*(((-B1-6*C1)*x(t(:,2)).^3 +...
(6*B1+30*C1)*x(t(:,2)).^2 + (-12*B1-48*C1)*x(t(:,2))+(8*B1+24*C1)));
ADD (corrected)
t1 = x0 <= -1;
t2 = x0 > -1 & x0 < 1;
t3 = x0 >= 1;
plot(x0(t1),y1(t1),'r'); hold on
plot(x0(t2),y1(t2),'g');
plot(x0(t3),y1(t3),'k');
6 个评论
Simon
2012-12-6
Andrei Bobrov
2012-12-6
see ADD in my answer
Simon
2012-12-6
Andrei Bobrov
2012-12-6
corrected
Simon
2012-12-6
Simon
2012-12-6
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