How to plot a piecewise defined function?

Hi
I want to plot a piecewise defined function. My Problem is, that the plot isn't right and I don't find the mistake... would be great, if somebody could help me!
function CubicSpline
clear all;
clc;
close all;
%CatmullRom:
B1=0;
C1=1/2;
x=-2:.01:2;
y1=zeros(size(x));
if abs(x)< 1,
y1=1/6*((12-(9*B1)-(6*C1))*abs(x).^3 +(-18+(12*B1)+(6*C1))*abs(x).^2 + (6-(2*B1)));
elseif 1 <= abs(x) < 2
y1 = 1/6*(((-B1-6*C1)*abs(x).^3 + (6*B1+30*C1)*abs(x).^2 + (-12*B1-48*C1)*abs(x)+(8*B1+24*C1)));
else y1 = 0;
end
figure(1);clf; hold on;
plot(x,y1,'r')%,x, y2, 'b', x, y3, 'g'
xlabel('X-Axis')
ylabel('Function values')
grid on;
legend({'CatmullRom: B = 0, C = 1/2'},'Location','EastOutside')

5 个评论

Your program is working, what is the expected result?
If B1 = 0, x = 0, abs(x) is 0 and as consequence the y1 value must be 1. When I plot it the y1-value at x=0 is 2
It is a waste of time to remove all loaded function after starting this function by "clear all". This does not even clean the local workspace, because there are no variables declared before.
Ah, thanks. Your're right!
I still have the problem to plot this function. Could anybody help me? Would be nice :-)

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回答(1 个)

B1=0;
C1=1/2;
x0 = -2:.1:2;
x=abs(x0);
y1=zeros(size(x));
t = [x < 1, x >= 1 & x < 2];
y1(t(:,1)) = 1/6*((12-(9*B1)-(6*C1))*x(t(:,1)).^3 +...
(-18+(12*B1)+(6*C1))*x(t(:,1)).^2 + (6-(2*B1)));
y1(t(:,2)) = 1/6*(((-B1-6*C1)*x(t(:,2)).^3 +...
(6*B1+30*C1)*x(t(:,2)).^2 + (-12*B1-48*C1)*x(t(:,2))+(8*B1+24*C1)));
ADD (corrected)
t1 = x0 <= -1;
t2 = x0 > -1 & x0 < 1;
t3 = x0 >= 1;
plot(x0(t1),y1(t1),'r'); hold on
plot(x0(t2),y1(t2),'g');
plot(x0(t3),y1(t3),'k');

6 个评论

Hey, thanks! But now I tried to plot y1, but it doesn't work... how can I plot y1?
plot(x, y1(t(:,:,1,2)),'r')
Sry for the stupid question..
The added Code doesn't work :(
plot(x(t(:,1)),y1(t(:,1)),'r',x(t(:,2)),y1(t(:,2)),'g',x(t(:,3)),(t(:,3)),'r');
This doesn't work, too :(
Hm... there's only a line with the values x=[-2:.1:2] and y=0
It still doesn'´t work. It could not be that difficult to plot this function. Would be great, if somebody could post the right code and explain it to me :)

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2012-12-6

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