'How to' Matrix
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I have an array with 0 s and 1s.
Example a colomn, 0 ,0 ,0 ,0 , 1.
Now the 1 is on the 5th row, I want to raise that to the first row.
So, in my code i want all the ones to go 4 steps up...
sounds easy, but how :) ?
5 个评论
Walter Roberson
2012-12-12
What if there is a 1 in the first 4 columns?
Also, should the new matrix have fewer columns?
TAB
2012-12-12
Then what should be left in 5th column (or row in your words) ?
Jan
2012-12-12
@Student: The question remains, what "raise to the first row" exactly means. At first I guess it is the "first column", but "raising" can be swapping, shifting, circular shifting, sorting, cropping or any procedure I cannot imagine currently.
Hello kity
2012-12-12
Jan
2012-12-12
Thanks for the clarification, Student. And what happens on the right margin? Is the result shorter, filled with zeros or ones or with the value of the last element?
回答（4 个）
Walter Roberson
2012-12-12
编辑：Walter Roberson
2012-12-12
0 个投票
Have you considered circshift() up by 4 rows?
0 个评论
Azzi Abdelmalek
2012-12-12
A=[0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 1]
for k=5:length(A)
if A(k)
b=A(k-4:k-1);
A(k-4)=1
A(k-4+1:k)=b
end
end
2 个评论
Hello kity
2012-12-12
Azzi Abdelmalek
2012-12-12
A=[0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 1]
for k=5:length(A)
if A(k) % If A(k) is equal to 1
b=A(k-4:k-1); % store value from k-4 to k-1 in b
A(k-4)=1 % replace value at k-1 by 1
A(k-4+1:k)=b % shift value stored in b
end
end
Andrei Bobrov
2012-12-12
编辑：Andrei Bobrov
2012-12-12
other way:
a - your vector - row (eg: [0 0 0 0 1])
n = numel(a);
out = a(hankel(1:n,[n,1:n-1]));
or
out = hankel(a,circshift(a,[0 1]));
1 个评论
Hello kity
2012-12-12
Some ideas:
x = [0, 0, 0, 0, 1];
index = find(x, 1, 'first');
y1 = x(index:end);
y2 = [x(index:end), zeros(1, index - 1)];
y3 = [x(index:end), ones(1, index - 1)];
y4 = [x(index:end), repmat(x(end), 1, index - 1)];
y5 = [x(index:end), x(1:index - 1)];
0 个评论
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2012-12-12
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