0 个投票

How to apply the finite difference to the following equation of y(t); 𝑑𝑦/𝑑𝑡 = 2𝑦^3 + 5. Given at t=0, y=1. Take time steps at Δt=0.001 and step the solution forward to t=0.25 ?

请先登录，再回答此问题。

 采纳的回答

KSSV
KSSV 2020-7-14

2 个投票

  1. Replace dy/dt with (y(t+1)-y(t))/dt
  2. Simplify it so that y(t+1) is on LHS and rest all on RHS. You will get a equation, RHS has all known values and LHS is the value which we seek.
  3. Initliaze the required arrays and first value of y i.e y = 1 at t=0;
  4. Create time array with specified time step. t = 0:0.001:0.25.
  5. Run a loop using time.

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Programming 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by