Index in position 2 exceeds array bounds (must not exceed 1).

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nag raj 2020-7-17

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/566364-index-in-position-2-exceeds-array-bounds-must-not-exceed-1

编辑： Walter Roberson 2020-7-17

function [Qr, lolb] = solveP3(Qr,Xr)
global K M H alpha beta0 delta_t Dmax B sigma_2 Lamda Pk q0 qF Sk F_1 w u tolerance
Ql = Qr;
l = 0;
tol = tolerance;
Lo = [];
for l = 1: 1000
    Qlt  = repelem(Ql,1,1,K);
    J = H^2 + sum( (Qlt - w).^2 ,1); 
    J = reshape(J, [M,K] );
    I = F_1*Pk*dB2dec(beta0)*(alpha/2)*log2(exp(1)) ./ (J .* (dB2dec(sigma_2) * dB2dec(Lamda) * J .^(alpha/2) + F_1*Pk*dB2dec(beta0)));
    A = log2(1 + (F_1*Pk*dB2dec(beta0)) ./ (dB2dec(sigma_2) * dB2dec(Lamda) * J .^(alpha/2)) );
    cvx_begin quiet
    variables Q(2,M)
    variables lo(1)
    expression LO(K)
    maximize (sum(lo))
    subject to:
    for k = 1 : K
        LO(k) = 0;
        for m = 1 : M
            Rlb = A(m,k) - I(m,k) * (sum_square_abs( Q(:,m) - u(:,k))) + I(m,k) * (sum_square_abs( Ql(:,m) - u(:,k)));
            LO(k) = LO(k) + Xr(m,k) * Rlb;
        end
        (1/(Sk/(B*delta_t))) * LO(k) >= lo; %Constraint (17)
    end
    for m = 2: M
       norm(Q(:,m) - Q(:,m-1)) <= Dmax;
    end
    Q(1,1) == q0(1);
    Q(2,1) == q0(2);
    Q(1,M) == qF(1);
    Q(2,M) == qF(2);
    cvx_end
    Lo = [Lo;sum(lo)];
    Ql = Q;
    if (l >= 2) &&(Lo(l) - Lo(l-1) < tol)
        break;
    end  
end
Qr = Q;
lolb = Lo(l);
end
function [dB] = dec2dB(dec)
dB = 10*log10(dec);
end
function [dec] = dB2dec(dB)
dec = 10.^(dB/10);
end

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nag raj 2020-7-17

It's function is used by another program where I got the results by execution. But individually run of this program occurs an index position error, is it happens such a case in general. And also ignoring for loop iteration I got an output but the loop is not working. I guess that the whole code will run in another program without any errors.

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