How to read & display multiple images from a folder

Question

Prashant Kashid 2012-12-24

3
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/57300-how-to-read-display-multiple-images-from-a-folder

编辑： DGM 2023-2-12

I have 20 TIFF images in MATLAB directory. How can I read them all & show them in different windows i.e. 20 windows for 20 images? I am new to MATLAB & currently using MATLAB & Simulink Release 2009a. After reading the images, how to display them one by one on screen?

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Shel 2018-8-24

在 MATLAB Online 中打开

I have series of 1600 dicom images with the name 6--12-1.dcm, 6--12-2.dcm, 6--12-3.dcm and so on. how can I read the sequence and do the filtering on images and save them in another folder? here is my code but it gives me errors, can you please help me to correct it:

source_dir=uigetdir([]); %I= dir('C:\Users\Shan\Desktop\CT Images')
pwd
d=dir([source_dir,'\6--12-*.dcm']);
totalfile=length(d); 
resultfolder='C:\Users\Shan\Desktop\CT Images\Median'
for i=1:totalfile
  fname=['6--12-',num2str(i), '.dcm'];
  indicom=dicomread(fullfile(source_dir, fname));
  
  subplot(1,2,1), imshow(indicom,[]);
  title(sprintf('original image number %d',i));
  
  medianfilter{i}=medfilt2(indicom{i},[4 4]);
  BasedFileName=sprint('%d.dcm',i);
  FilteredFileName=fullfile(resultfolder,BasedFileName)
  dicomwrite(medianfilter, FilteredFileName);
  
  subplot(1,2,2), imshow(medianfilter,[]);
  title(sprintf('median filtered image number %d',i));
end

Actually, I have asked it in several places but I could not find the answer, I would appreciate it if you could help me to solve this problem pleasee!

shobhana 2023-2-3

hi can you help me regarding MATLAB in test image i wanna run multiple images folders so how i can run group of images in the matlab

Image Analyst 2023-2-3

在 MATLAB Online 中打开

@shobhana try this:

% Process a sequence of files.
filePattern = fullfile(pwd, '*.png');
imds = imageDatastore(filePattern) % Create an image Datastore
% Get all filenames into one cell array.  Filenames have the complete path (folder prepended).
allFileNames = imds.Files;
numFiles = numel(imds.Files);
for k = 1 : numel(allFileNames)
    % Get this file name.
    fullFileName = allFileNames{k};
    fprintf('Processing %s\n', fullFileName);
    % Now do something with fullFileName, such as passing it to imread.
end

If that does not work for you then try starting your own question so we can figure it out.

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Answer 1

Sabarinathan Vadivelu 2012-12-24

28
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/57300-how-to-read-display-multiple-images-from-a-folder#answer_69313

编辑：MathWorks Support Team 2018-11-27

在 MATLAB Online 中打开

Create a datastore by specifying the location of your image files.

location = 'E:\New Folder\*.tif';       %  folder in which your images exists
ds = imageDatastore(location)         %  Creates a datastore for all images in your folder

Loop through the datastore, read and display each image in its own window.

while hasdata(ds) 
    img = read(ds) ;             % read image from datastore
    figure, imshow(img);    % creates a new window for each image
end

For more information on reading and managing a collection of image files, see:

https://www.mathworks.com/help/matlab/ref/matlab.io.datastore.imagedatastore.html

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Md. Mostafizur Rahman 2017-11-28

Hi, I also apply this code but it can't show the image in the different window. But in the Workspace, it shows an empty array of i.

Can you tell me what's I wrong?

Bharath AS 2019-3-1

移动：DGM 2022-12-20

Thanks sabarinathan and matlab support team ..it helped

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Answer 2

Delowar Hossain 2015-10-19

2
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/57300-how-to-read-display-multiple-images-from-a-folder#answer_196462

编辑：Walter Roberson 2015-10-19

在 MATLAB Online 中打开

jpgFiles = dir('*.jpg');
numFiles = length(jpgFiles);
mydata = cell(1,numFiles);
% mydata = zeros(numFiles);
for k = 1:numFiles
    mydata{k} = imread(jpgFiles(k).name);
end
for k = 1:numFiles
%     subplot(4,5,k);
    figure;
    imshow(mydata{k});
end

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Noor Fatima 2022-4-4

@Walter Roberson

I want to make a sub-plot with all the images in directory, although ypu have commented subplot line but I'm not getting the point . May I please request you that how can I plot all those image in to one plot?

Image Analyst 2022-4-4

@Noor Fatima, try montage() or imtile().

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Answer 3

Image Analyst 2012-12-24

1
链接

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https://ww2.mathworks.cn/matlabcentral/answers/57300-how-to-read-display-multiple-images-from-a-folder#answer_69344

You might want to consider the montage() function in the Image Processing Toolbox.

Otherwise you can use set(handle, 'Position'...) to arrange your figures on screen.

There is also a way to "dock" figures as tabbed windows in a single figure that you can size to take up the whole screen, though I forget what the code is to dock multiple figures into one. I'm sure Jan or someone else knows though.

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ayushi 2016-7-4

编辑：ayushi 2016-7-4

在 MATLAB Online 中打开

sir suppose there is a folder and there are some images of .png format and i want to get the features of all those images one by one by feeding them to the code given below :

   function [features]=feature_extractor_2d(image)
  %this function zones the input image and extracts features for each zone.
% skeletonizing image
image=bwmorph(image,'skel',inf);
%selecting the universe of discourse
image=discourser(image);
original_image=image;% just backing up the orginal image
row=size(image,1);
column=size(image,2);
% we have to ceil this no.s to the nearest multiple of 3 since
% 3x3 windowing is used
% first we have to ensure that image consists of minimum 9 rows and minimum
% 9 columns
add_rows=0; %no of additional rows to make min of 9x9 matrix
add_columns=0; % similar for columns
if row<9
    add_rows=9-row;
end
if column<9
    add_columns=9-column;
end
if mod(add_rows,2)==0
    image=[zeros(add_rows/2,column);image;zeros(add_rows/2,column)];
else
    image=[zeros((add_rows-1)/2,column);image;zeros((add_rows+1)/2,column)];
end
%appending rows of zeros
%after above op, no.of rows changes so it should be updated
%equal no of rows should be added on top and bottom
row=size(image,1);
if mod(add_columns,2)==0
    image=[zeros(row,(add_columns)/2),image,zeros(row,(add_columns)/2)];
else
    image=[zeros(row,(add_columns-1)/2),image,zeros(row,(add_columns+1)/2)];
end
column=size(image,2); %updating the column value
n_rows=ceil(row/3)*3-row; % no of rows of zeros to be added
n_columns=ceil(column/3)*3-column; % no of columns of zeros to be added
% assume row=4, so 2 rows of zeros should be added. ceil(4/3)*3 will return
% 6 which is nearest multiple of 3 to 4 from right side. So n_rows will
% contain no.of rows to be added to the image.
if mod(n_rows,2)==0
    image=[zeros(n_rows/2,column);image;zeros(n_rows/2,column)];
else
    image=[zeros((n_rows-1)/2,column);image;zeros((n_rows+1)/2,column)];
end
%appending rows of zeros
%after above op, no.of rows changes so it should be updated
%equal no of rows should be added on top and bottom
row=size(image,1);
if mod(n_columns,2)==0
    image=[zeros(row,(n_columns)/2),image,zeros(row,(n_columns)/2)];
else
    image=[zeros(row,(n_columns-1)/2),image,zeros(row,(n_columns+1)/2)];
end
column=size(image,2); %updating the column value
% so now the image can be divided into 3x3 zones
% here in above code some more features are to be added, like if two rows
% of zeros are to be added then one on either side of the image and
% similarily for columns.
column_zone_height=row;
column_zone_width=column/3;
%say at this point image is 12x9, so no.of rows in each column zone should be
%12, whereas columns should be 9/3=3. This is stored in variables zone
%height and width
column_zone1=image(1:column_zone_height,1:column_zone_width);
column_zone2=image(1:column_zone_height,(column_zone_width+1):2*column_zone_width);
column_zone3=image(1:column_zone_height,(2*column_zone_width+1):end);
row_zone_height=row/3;
row_zone_width=column;
row_zone1=image(1:row_zone_height,1:row_zone_width);
row_zone2=image((row_zone_height+1):2*row_zone_height,1:row_zone_width);
row_zone3=image((2*row_zone_height+1):end,1:row_zone_width);
% feature_vectors
column_zone1_features=lineclassifier(column_zone1);
column_zone2_features=lineclassifier(column_zone2);
column_zone3_features=lineclassifier(column_zone3);
row_zone1_features=lineclassifier(row_zone1);
row_zone2_features=lineclassifier(row_zone2);
row_zone3_features=lineclassifier(row_zone3);
% this is a feature called euler no...euler no. is diff between no.of
% objects and holes in that image
euler=bweuler(image);
features=[column_zone1_features;column_zone2_features;column_zone3_features;row_zone1_features;row_zone2_features;row_zone3_features];
features=[reshape(features',numel(features),1);euler];
% here the region properties of the image are going to be considered
stats=regionprops(bwlabel(image),'all');
skel_size=numel(image);
%convexarea=(stats.ConvexArea)/skel_size;
eccentricity=stats.Eccentricity;
extent=stats.Extent;
%filledarea=(stats.FilledArea)/skel_size;
%majoraxislength=(stats.MajorAxisLength)/skel_size;
%minoraxislength=(stats.MinorAxisLength)/skel_size;
orientation =stats.Orientation;
% this are the regional features
regional_features=[eccentricity;extent;orientation];

i tried following procedure but its not working properly and not getting how to do this work:

srcFiles = dir('C:\Users\Omm\Downloads\multicharacterrec\*.png');  % the folder in which ur images exists
    for i = 1 : length(srcFiles)
        filename = strcat('C:\Users\Omm\Downloads\multicharacterrec\',srcFiles(i).name);
  function()
  %something something %
    end
end

ayushi 2016-7-4

在 MATLAB Online 中打开

it's showing following error sir :(

Function definitions are not permitted in this context.

code:

srcFiles = dir('C:\Users\Omm\Downloads\multicharacterrec\*.png');  % the folder in which ur images exists
for i = 1 : length(srcFiles)
        filename = strcat('C:\Users\Omm\Downloads\multicharacterrec\',srcFiles(i).name);
thisImage = imread(filename);
function [features]=feature_extractor_2d(thisImage)
 %this function zones the input image
% and extracts features for each zone.
% skeletonizing image
image=bwmorph(image,'skel',inf);
%selecting the universe of discourse
image=discourser(image);
original_image=image;% just backing up the orginal image
row=size(image,1);
column=size(image,2);
% we have to ceil this no.s to the nearest multiple of 3 since
% 3x3 windowing is used
% first we have to ensure that image consists of minimum 9 rows and minimum
% 9 columns
add_rows=0; %no of additional rows to make min of 9x9 matrix
add_columns=0; % similar for columns
if row<9
    add_rows=9-row;
end
if column<9
    add_columns=9-column;
end
if mod(add_rows,2)==0
    image=[zeros(add_rows/2,column);image;zeros(add_rows/2,column)];
else
    image=[zeros((add_rows-1)/2,column);image;zeros((add_rows+1)/2,column)];
end
%appending rows of zeros
%after above op, no.of rows changes so it should be updated
%equal no of rows should be added on top and bottom
row=size(image,1);
if mod(add_columns,2)==0
    image=[zeros(row,(add_columns)/2),image,zeros(row,(add_columns)/2)];
else
    image=[zeros(row,(add_columns-1)/2),image,zeros(row,(add_columns+1)/2)];
end
column=size(image,2); %updating the column value
n_rows=ceil(row/3)*3-row; % no of rows of zeros to be added
n_columns=ceil(column/3)*3-column; % no of columns of zeros to be added
% assume row=4, so 2 rows of zeros should be added. ceil(4/3)*3 will return
% 6 which is nearest multiple of 3 to 4 from right side. So n_rows will
% contain no.of rows to be added to the image.
if mod(n_rows,2)==0
    image=[zeros(n_rows/2,column);image;zeros(n_rows/2,column)];
else
    image=[zeros((n_rows-1)/2,column);image;zeros((n_rows+1)/2,column)];
end
%appending rows of zeros
%after above op, no.of rows changes so it should be updated
%equal no of rows should be added on top and bottom
row=size(image,1);
if mod(n_columns,2)==0
    image=[zeros(row,(n_columns)/2),image,zeros(row,(n_columns)/2)];
else
    image=[zeros(row,(n_columns-1)/2),image,zeros(row,(n_columns+1)/2)];
end
column=size(image,2); %updating the column value
% so now the image can be divided into 3x3 zones
% here in above code some more features are to be added, like if two rows
% of zeros are to be added then one on either side of the image and
% similarily for columns.
column_zone_height=row;
column_zone_width=column/3;
%say at this point image is 12x9, so no.of rows in each column zone should be
%12, whereas columns should be 9/3=3. This is stored in variables zone
%height and width
column_zone1=image(1:column_zone_height,1:column_zone_width);
column_zone2=image(1:column_zone_height,(column_zone_width+1):2*column_zone_width);
column_zone3=image(1:column_zone_height,(2*column_zone_width+1):end);
row_zone_height=row/3;
row_zone_width=column;
row_zone1=image(1:row_zone_height,1:row_zone_width);
row_zone2=image((row_zone_height+1):2*row_zone_height,1:row_zone_width);
row_zone3=image((2*row_zone_height+1):end,1:row_zone_width);
% feature_vectors
column_zone1_features=lineclassifier(column_zone1);
column_zone2_features=lineclassifier(column_zone2);
column_zone3_features=lineclassifier(column_zone3);
row_zone1_features=lineclassifier(row_zone1);
row_zone2_features=lineclassifier(row_zone2);
row_zone3_features=lineclassifier(row_zone3);
% this is a feature called euler no...euler no. is diff between no.of
% objects and holes in that image
euler=bweuler(image);
features=[column_zone1_features;column_zone2_features;column_zone3_features;row_zone1_features;row_zone2_features;row_zone3_features];
features=[reshape(features',numel(features),1);euler];
% here the region properties of the image are going to be considered
stats=regionprops(bwlabel(image),'all');
skel_size=numel(image);
%convexarea=(stats.ConvexArea)/skel_size;
eccentricity=stats.Eccentricity;
extent=stats.Extent;
%filledarea=(stats.FilledArea)/skel_size;
%majoraxislength=(stats.MajorAxisLength)/skel_size;
%minoraxislength=(stats.MinorAxisLength)/skel_size;
orientation =stats.Orientation;
% this are the regional features
regional_features=[eccentricity;extent;orientation];
end

Image Analyst 2016-7-5

That does not make sense to me. Like I said, remove the word "function" when you actually call the function from your main routine. The word "function" should only be where you actually define/write the function, NOT where you call it from some other function.

ayushi 2016-7-6

ok sir

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Answer 4

murk hassan memon 2018-2-11

0
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/57300-how-to-read-display-multiple-images-from-a-folder#answer_304543

编辑：Image Analyst 2018-2-11

在 MATLAB Online 中打开

srcFiles = dir('E:\New Folder\IM_*.dcm');
for i = 1 : length(srcfiles)
  filename = strcat('E:\New Folder\',srcFiles(i).name);
  I = dicomread(filename);
  figure, imshow(I);
end

i have tried this code but it is not displaying any output on screen just showing number of images and there names on workspace. kindly help me that how to read and display multiple images from folder

I have also tried this code

myfile=dir('C:\Users\Documents\*.jpg'); % the folder inwhich ur images exists
for i = 1 : length(myfile)
    filename = strcat('C:\Users\Documents\',myfile(i).name);
    k=importdata(filename);
end

but it displays all images on one screen so that the last image is displayed, but I want all these images on different window screen so what should I do?

Help me out please

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AP 2020-6-9

Hello sir... i have tried this code but it is giving me error. Like Reference to non-existent field 'folder'.

Please guide me through this.

Walter Roberson 2020-6-12

在 MATLAB Online 中打开

AP, you are probably using an old MATLAB release.

folder = 'C:\Users\Documents\';
filePattern = fullfile(folder, '*.jpg');
myFiles = dir(filePattern); % the folder inwhich ur images exists
rows = ceil(sqrt(length(myFiles)))
for k = 1 : length(myFiles)
  fullFileName = fullfile(folder, myFiles(k).name);
  subplot(rows, rows, k);
  imshow(fullFileName);
  title(myFiles(k).name, 'Interpreter', 'none');
  drawnow;
end
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0, 0.04, 1, 0.96]);

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Answer 5

Shel 2019-2-4

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/57300-how-to-read-display-multiple-images-from-a-folder#answer_359448

在 MATLAB Online 中打开

Hello,

I have 1986 tif images and now I want to read the series but I do not know how I should do would you please guide me?

How can I read my series of images?

here is the name of my files and my code:

names:

T4-1-140-0001

T4-1-140-0002

...

T4-1-140-1986

code:

clc
clear all
image_folder='C:\Users\Shel\1';
source_dir=uigetdir([]);
d=dir([source_dir,'\T4-1-140-000*.tif']);
filename=dir(fullfile(image_folder, 'T4-1-140-*.tif'));
H='result.txt';
file1=fopen(H,'w');
total_image=numel(filename);
tic
for n=1:total_image
    fname=['T4-1-140-000',num2str(i), '.tif'];
        inimg=imread(fullfile(source_dir, fname))
        %f=fullfile(image_folder,filename(n).name);
        %indicom=imread(f);
        image_totpx=numel(inimg);
        miangin=mean(mean(inimg));
        mmax = max(inimg(:));
        mmin=min(min(inimg));
        img_NB=length(inimg(inimg==255));
        area=img_NB
        P=area/image_totpx;
        fprintf(file1,' %2.0f  %10s %2.5f    \r\n', i,  '   ', p);
    
end
toc
fclose(file1);

Thank you very much

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Image Analyst 2019-2-4

在 MATLAB Online 中打开

Change this:

for n=1:total_image
    fname=['T4-1-140-000',num2str(i), '.tif'];

to this

for n=1:total_image
    fname=sprintf('T4-1-140-000%4.4d.tif', n);

You need to use n instead of i since n is the loop iterator, and use 4 digits for the number, which num2str() can't do, but sprintf() can.

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Answer 6

sarah fteih 2019-10-10

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/57300-how-to-read-display-multiple-images-from-a-folder#answer_395671

编辑：DGM 2023-2-12

在 MATLAB Online 中打开

hi

i have done this code for k means algorithm segmenation as a part of image processing:

%% K-means Segmentation (option: K Number of Segments)
clc
clear all
close all
%% Load Image
I = im2double(imread('D:\PHD\Data\ADNI\Batch Output 2019-06-13-1234\ADNI_002_S_0295_MR_Axial_PD_T2_FSE__br_raw_20060418201146219_97_S13404_I13718.jpg'));                    % Load Image
F = reshape(I,size(I,1)*size(I,2),3);                 % Color Features
%% K-means
K     = 4;                                            % Cluster Numbers
CENTS = F( ceil(rand(K,1)*size(F,1)) ,:);             % Cluster Centers
DAL   = zeros(size(F,1),K+2);                         % Distances and Labels
KMI   = 10;                                           % K-means Iteration
for n = 1:KMI
    for i = 1:size(F,1)
        for j = 1:K  
            DAL(i,j) = norm(F(i,:) - CENTS(j,:));      
        end
        [Distance, CN] = min(DAL(i,1:K));               % 1:K are Distance from Cluster Centers 1:K 
        DAL(i,K+1) = CN;                                % K+1 is Cluster Label
        DAL(i,K+2) = Distance;                          % K+2 is Minimum Distance
    end
    for i = 1:K
        A = (DAL(:,K+1) == i);                          % Cluster K Points
        CENTS(i,:) = mean(F(A,:));                      % New Cluster Centers
        if sum(isnan(CENTS(:))) ~= 0                    % If CENTS(i,:) Is Nan Then Replace It With Random Point
            NC = find(isnan(CENTS(:,1)) == 1);           % Find Nan Centers
            for Ind = 1:size(NC,1)
                CENTS(NC(Ind),:) = F(randi(size(F,1)),:);
            end
        end
    end
end
X = zeros(size(F));
for i = 1:K
    idx = find(DAL(:,K+1) == i);
    X(idx,:) = repmat(CENTS(i,:),size(idx,1),1); 
end
T = reshape(X,size(I,1),size(I,2),3);
%% Show
figure()
subplot(121); imshow(I); title('original')
subplot(122); imshow(T); title('segmented')
disp('number of segments ='); disp(K)

i have more than 100 images and i want read them at this code and get the output of segmenation on new folder on my pc

please please can you help me?????

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Image Analyst 2019-10-10

The code I gave in my comment here should work.

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16 个评论
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26 个评论
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