Graphing exponential function with imaginary term

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Nachiket Kortikar
评论： Nachiket Kortikar 2020-8-8
I am trying to plot a function where my amplitude is dependant on varaiable say z. and the phase is depentant on theta which is varying form -pi/2 to pi/2.
I get error as
empty double row vector
I saw some other plots. I don't understnd why it doens't work for me.
clear all;
clc;
close all;
pi = 3.1415;
theta = linspace(-pi/2,pi/2,0.01)
z = linspace(-pi/2,pi/2,0.01)
g2 = 5;
g3 = 0.5;
sigma0 = 0.05;
B = -(3*g2*sigma0-8*g3*sigma0)/((2*g2*sigma0))
D = (3*g2*sigma0-8*g3*sigma0)^2/((6*g2))
sigma0 = 0.05;
sigma = sigma0*(1-(B./(1+D.*z.^2)))
psi = sqrt(sigma).*exp(1i.*theta)
figure()
plot3(theta,real(psi),imag(psi))
% plot3(z,theta,imag(psi))
% hold on
grid on
xlabel('\psi', 'Rotation',-30)
ylabel('Real Axis', 'Rotation',10)
zlabel('Imag Axis')

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采纳的回答

Cris LaPierre
Cris LaPierre 2020-8-3
I suspect it has to do with how you define theta and z. Check out the documentation for linspace. The last number is the nubmer of data points you want. You have asked for 0.01, which is not possible, so theta and z are both empty vectors.
theta = linspace(-pi/2,pi/2,300);
z = linspace(-pi/2,pi/2,300);
If you want a specific increment, use the colon operator instead
theta = -pi/2:0.01:pi/2;
z = -pi/2:0.01:pi/2;

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